Question

How do you solve an equation by completing the square? Example: D-8" id="TexFormula1" title=" x^{2}+6x=-8" alt=" x^{2}+6x=-8" align="absmiddle" class="latex-formula">

Answer 1

X²+6x+8=0
x²+2*3x+9-1=0
(x+3)²-1=0
(x+3)²-1²=0
(x+3-1)(x+3+1)=0
(x+2)(x+4)=0
x₁=-2
x₂=-4
Answer: x₁=-2,  x₂=-4

Answer 2

$x^2+6x=-8\\ x^2+6x+9=1\\ (x+3)^2=1\\ x+3=1 \vee x+3=-1\\ x=-2 \vee x=-4$