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tankabanditka [31]
3 years ago
8

Y=1/4x-2 write in standard form

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
5 0

Answer: hvdwc bc3uich3jbf 3ichb3lfbd3piujbvler

ion bro

Step-by-step explanation:

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You are given a cube with a length of 2.5 cm a width of 2.5 cm and a heigh of 2.5 cm and its mass is 295 g what is the density
Klio2033 [76]
Density = mass/volume
Volume = length x width x height
Volume = 2.5 x 2.5 x 2.5 
             = 15.625 cm^3
Density = 295/15.625
             = 18.88 g/cm^3
4 0
4 years ago
Which table represents a function?
alina1380 [7]
Table B is the answer because each x value has only 1 y value
4 0
3 years ago
I need help on question 2 i need the simplified answer and the restrictions
Anastaziya [24]

Answer:

x cannot be 5 or -3.

\frac{x+5}{x+3}

Step-by-step explanation:

The restrictions for a fraction is that the bottom cannot be 0.

So if we find when the bottom is 0 we have found the values that x cannot be.

Let's solve x^2-2x-15=0.

Since the coefficient of x^2 is 1 all we have to do is find two numbers whose product is -15 and whose sum is -2.

Those numbers are -5 and 3 since (-5)(3)=-15 and (-5)+(3)=-2.

So the factored form of the equation is:

(x-5)(x+3)=0

This means either x-5=0 or x+3=0.

We do have to solve both.

x-5=0 can be solved by adding 5 on both sides.

x-5+5=0+5

x+0=0+5

x=5

x+3=0 can be solved by subtracting 3 on both sides.

x+3-3=0-3

x+0=0-3

x=-3

So x can be any number except x=5 or x=-3.

We already factored the bottom as (x-5)(x+3).

The top is a difference of squares, x^2-a^2,

which can be factored as (x-a)(x+a).

So the top factors as (x-5)(x+5).

The fraction can then be written as:

\frac{x^2-25}{x^2-2x-15}=\frac{(x-5)(x+5)}{(x-5)(x+3)}

This can further simplified assuming x is not 5 we can write it as \frac{x+5}{x+3}.  I canceled the common factor of (x-5).

5 0
3 years ago
Hlp me with this math problem
zaharov [31]

Answer:

0.5l+0.2s

Step-by-step explanation:

0.10x5<em>l</em> equals 0.5<em>l</em>

0.10x2<em>s</em> equals 0.2<em>s</em>

7 0
3 years ago
Brennanhasalreadytaken17quizzesduringpastquarters,andheexpectstohave2quizzesduringeachweekofthisquarter.Howmanyweeksofschoolwill
jeka94
Brennan will have to take 8 more quizzes to get to 25
8 0
3 years ago
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