Here, A.P. is 3x-1, 4x, 5x+1, 4
i) Common difference (d)
(5x-1) - 4x = x - 1
It would be same as 4 - (5x-1) = 4-5x+1 = 5-5x
Now, x - 1 = 5 - 5x
5x + x = 5 + 1
6x = 6
x = 6/6
x = 1
So, Common difference would be 1
ii) Eight term will be: a + (n-1)d = 2 + (8-1)2 = 2+7(2) = 2+14 = 16
So, eight term would be 16
Hope this helps!
Answer:
A. {e, h}
Step-by-step explanation:
In a Venn diagram, the set of elements in any intersection can simply be visualised. The elements contained in the region where the circles representing different sets overlap, are the set of elements of intersection.
In the Venn diagram given, the set of elements contained in the region where the circles representing A and B overlap are {e, h}.
{e, h} is common to both set A and set B.
The simplified answer is 27m^2
Answer:
If every line parallel to two lines intersects both regions in line segments of equal length, then the two regions have equal areas. In the case of your problem, every line parallel to the bases of the two parallelograms will intersect them in lines segments, each with a width of ℓ.
All exercises involve the same concept, so I'll show you how to do the first, then you can apply the exact same logic to all the others.
The first thing you need to know is that, when a certain quantity multiplies a parenthesis, you can distribute that number to every element in the parenthesis. This means that
So, 
is multiplying the parenthesis involving 
and 
, and we distributed it: multiplies both and in the final result.
Secondly, you have to know how to recognize like terms, because they are the only terms you can sum. Two terms can be summed if they have the same literal expression. So, for example, you cannot sum 
, and neither 
exponents count.
But you can su, for example,
or
So, take for example exercise 9:
We distribute the 1.2 through the first parenthesis:
And you can distribute the negative sign through the second parenthesis (it counts as a -1 to distribute):
So, the expression becomes
Now sum like terms:
