The answer is simplified to 15
Answer:
Yes, I can reject the null hypothesis with 95% confidence.
Step-by-step explanation:
Critical value t(63) = 1.99
p-value = 0.03
Confidence level (C) = 95% = 0.95
Significance level = 1 - C = 1 - 0.95 = 0.05
Conclusion:
Reject the null hypothesis because the p-value 0.03 is less than the significance level 0.05.
There is only one set of coordinates that satisfies this equations. That set is (5,0). I hope this helps!
Here, we may use Geometric Progression
The sequence follows as:
27, 18,12,...
The first term (a)= 27
27/18 = 18/12
common ratio = 1.5
Let fourth term be x
Therefore , 12/x = 1.5
=> x= 12/1.5 = 8
