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Ivanshal [37]
3 years ago
15

The Richter scale is used to measure the intensity of an earthquake. If E, measured in joules, is the energy released during an

earthquake, then the magnitude is given by where joules.
If joules of energy are released during an earthquake, what is the magnitude of the earthquake?

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
8 0

Answer:

You have given no numbers, so I attached a table I found at the University of Wichita.  

Step-by-step explanation:


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Step-by-step explanation:

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Please Help Will give 20 points
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8 0
3 years ago
An angle measures 18.6° less than the measure of its complementary angle. What is the measure of each angle?
weeeeeb [17]

Answer:

X = 35.7 Y=54.3

Step-by-step explanation:

Let the 2 angles be called X and Y were X is the smaller angle

we know that both angles are complementary therefore
X+Y=90

X = Y - 18.6 ( Given )

Y - 18.6 + Y = 90 ( substitution)

2Y = 90 + 18.6

Y = 108.6/2

Y=54.3

X= Y-18.6= 54.3-18.6 = 35.7

Check : X + Y = 35.7+54.3=90

6 0
2 years ago
Solve: 2cos(x)-square root 3=0 for 0 less than x less than 2 pi
Leona [35]

Answer:

The general solution of   cos x = cos(\frac{\pi }{6})   is  

                                                x = 2nπ±\frac{\pi }{6}

The general solution values  

                                 x = - \frac{\pi }{6}  and x = \frac{\pi }{6}

Step-by-step explanation:

Explanation:-

Given equation is  

                              2cosx-\sqrt{3} =0  for 0

                              2cosx =\sqrt{3}

Dividing '2' on both sides, we get

                             cos x =\frac{\sqrt{3} }{2}

                             cos x = cos(\frac{\pi }{6})

<em>General solution of cos θ = cos ∝ is θ = 2nπ±∝</em>

<em>Now The general solution of   </em>cos x = cos(\frac{\pi }{6})<em>   is  </em>

<em>                                                 x = 2nπ±</em>\frac{\pi }{6}<em></em>

put n=0

x = - \frac{\pi }{6}  and x = \frac{\pi }{6}

Put n=1  

x = 2\pi +\frac{\pi }{6} = \frac{13\pi }{6}

x = 2\pi -\frac{\pi }{6} = \frac{11\pi }{6}

put n=2

x = 4\pi +\frac{\pi }{6} = \frac{25\pi }{6}

x = 4\pi -\frac{\pi }{6} = \frac{23\pi }{6}

And so on

But given 0 < x< 2π

The general solution values  

                                 x = - \frac{\pi }{6}  and x = \frac{\pi }{6}

                               

6 0
3 years ago
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