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Stels [109]
2 years ago
10

2/3 times 3 times 2/7

Mathematics
2 answers:
fomenos2 years ago
7 0

Answer:

4/7

Step-by-step explanation:

2/7 x 3= 6/7. 6/7× 2/3=4/7

natali 33 [55]2 years ago
5 0

Answer:

4/7

Step-by-step explanation:

⅔•3 equals 6/3

6/3• 2/7 equals 12/21 which equals 4/7

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A crew of highway works paved 1/5 mile in 1/8 hour if they work at the same rate how much will they pave in one hour
Allushta [10]

Answer:

a 1.6 miles

Step-by-step explanation:

1/8 hour=7.5

60/7.5=8

1/5*8=1.6

4 0
3 years ago
Jared and Morgan are making two gazebos in the shape of regular polygons, Jared's gazebo is a heptagon
bezimeni [28]

Answer:

10.4 :)

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
I need a percentage, and 60 doesn't work. Please help!
alukav5142 [94]

The probability that you will wait for at most 5 seconds is 6.7%

<h3>How to determine the probability?</h3>

The given parameters are:

Green = 40

Yellow = 5

Red = 30

When you spend a maximum of 5 seconds, it means that you get to the traffic light at the yellow cycle.

The probability is then calculated as:

P(Yellow) = 5/(40 + 5 + 30)

Evaluate

P(Yellow) = 6.7%

Hence, the probability that you will wait for at most 5 seconds is 6.7%

Read more about probability at:

brainly.com/question/15246027

#SPJ1

5 0
2 years ago
A catering company loses $110 as a result of a delay.
tatyana61 [14]

Answer:What you have to do first is you have 5 owners correct? Well you take anything they're sharing in this case it's delay/debt, so you divide $110 by 5 and you should get $22. This means that each owner would have to pay $22 for the delay.

ANS -22

Brainly please

4 0
3 years ago
DIscrete Math
Daniel [21]

Answer:

Step-by-step explanation:

As the statement is ‘‘if and only if’’ we need to prove two implications

  1. f : X \rightarrow Y is surjective implies there exists a function h : Y \rightarrow X such that  f\circ h = 1_Y.
  2. If there exists a function h : Y \rightarrow X such that  f\circ h = 1_Y, then f : X \rightarrow Y is surjective

Let us start by the first implication.

Our hypothesis is that the function f : X \rightarrow Y is surjective. From this we know that for every y\in Y there exist, at least, one x\in X such that y=f(x).

Now, define the sets X_y = \{x\in X: y=f(x)\}. Notice that the set X_y is the pre-image of the element y. Also, from the fact that f is a function we deduce that X_{y_1}\cap X_{y_2}=\emptyset, and because  f the sets X_y are no empty.

From each set X_y  choose only one element x_y, and notice that f(x_y)=y.

So, we can define the function h:Y\rightarrow X as h(y)=x_y. It is no difficult to conclude that f\circ h(y) = f(x_y)=y. With this we have that f\circ h=1_Y, and the prove is complete.

Now, let us prove the second implication.

We have that there exists a function  h:Y\rightarrow X  such that f\circ h=1_Y.

Take an element y\in Y, then f\circ h(y)=y. Now, write x=h(y) and notice that x\in X. Also, with this we have that f(x)=y.

So, for every element y\in Y we have found that an element x\in X (recall that x=h(y)) such that y=f(x), which is equivalent to the fact that f is surjective. Therefore, the prove is complete.

3 0
2 years ago
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