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irga5000 [103]
4 years ago
11

Kendra had twice as much money as kareem. Kendra later spent $8 and kareem earned $6. By then,the two had the same amount of mon

ey. How much money did each have originally?
Mathematics
1 answer:
Svet_ta [14]4 years ago
6 0

Answer:

x = 2y

x - 8 = y + 6

replace x by 2y in the second equation

2y - 8 = y + 6

y - 8 = 6

y = 14

x = 2*14 = 28

Kendra had $28 and Kareem had $14.

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The least common denominator of 1/3, 5/8, and 1/2 is:
andrey2020 [161]

Answer: 24

Step-by-step explanation:

You need to find the common denominator. In the case 24 is the least one because when you multiply 3 by 8, you finally have a common denominator for all three.

If you found this answer helpful, give it a five-star rating and a thanks! It would really mean a lot!

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The air quality was tested in many office buildings in two cities. The results of the testing is shown in this box plots.
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A C & D If The Air Quality Was Tested .
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Please help me out if you can!
Mkey [24]

Ok so we know that consecutive angles are supplementary and the diagonals bisect the angels so

2x-15+3x=90

5x=105

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3 years ago
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A public beach in Florida charges non residents $8 per day for a fishing license and $2.50 per day for live bait. Florida reside
melamori03 [73]

For a non-resident:

C_{nr}=8d+2.5d=10.5d

For a resident:

C_{r}=114+1d

We want to know the number of days d such that the two costs are equal ie \{d|C_{nr}(d)=C_{r}(d)\}

To do this set the two costs equal to each other:

C_{nr}=C_{r}

10.5d=114+1d

And solve for d:

10.5d-1d=114+1d-1d

9.5d=114

d=\frac{114}{9.5}

d=12

The costs will be equal when a resident and a non-resident each use the beach for 12 days.



3 0
4 years ago
One number is 7 more than another. The difference between their squares is 161. What are the numbers?
olga nikolaevna [1]
Let's say the numbers are "a" and "b"

now, we know one of them is 7 more than the other, so hmmm let's say "b" is 7 more than "a", so b = a + 7

the difference of their squares is 161, alrite

\bf a^2-b^2=161\qquad b=a+7\implies a^2-(a+7)^2=161
\\\\\\
a^2-(a^2+14a+49)=161\implies \underline{a^2-a^2}-14a-49=161
\\\\\\
-14a-49=161\implies -49-161=14a\implies -210=14a
\\\\\\
\cfrac{-210}{14}=a

and surey you know how much that is

now, what's "b"? well, b = a + 7
3 0
4 years ago
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