All categories

3 years ago

How many moles H2SO4 are needed to make 85 mL of .750 M solution?

Chemistry

1 answer:

grin007 [14]3 years ago

4 0

Answer:

0.06375 mole

Explanation:

The following data were obtained from the question:

Volume = 85mL

Molarity of H2SO4 = 0.750 M

Mole of H2SO4 =..?

Next, we'll convert 85mL to a value in L.

This is illustrated below:

1000mL = 1L

Therefore, 85mL = 85/1000 = 0.085L

Now, we can obtain the number of mole of H2SO4 as follow:

Molarity is simply defined as the mole of solute per unit litre of the solution i.e

Molarity = mole /Volume

Mole = Molarity x Volume

Mole of H2SO4 = 0.750 x 0.085

Mole of H2SO4 = 0.06375 mole

Therefore 0.06375 mole of H2SO4 is needed to make the solution

You might be interested in

Suppose the volume of a container is decreased, but the same number of gas molecules is present at the same temperature. What wi

charle [14.2K]

Answer: Option (C) is the correct answer.

Explanation:

When the volume of a container is decreased and same number of gas molecules are present inside the container at the same temperature then it means that more number of gas molecules are spread per unit volume.

As earlier when the volume of container was more then the molecules were widely spread inside the container but on decreasing the volume of container, molecules come closer to each other and hence there will be increase in molecules per unit volume.

6 0

3 years ago

Match the word to the part of the wave. (Lesson 4.02)

Alenkinab [10]

Answer:

1 A. Wavelength 2. B. Crest 3. C. Amplitude 4. D. Trough

Explanation:

I cant really give an explanation but I hope it helps

3 0

3 years ago

Location E is located at the Tropic of Cancer, while location F is at the equator. Which location is likely to be warmer at the

Stells [14]

The answer is "Location E, because Earth's axis is tilted towards the sun" :D

6 0

2 years ago

How many grams of P2Cl5 are produced if 2.00 moles of P reacts with an excess of Cl2?

Roman55 [17]

Answer:

$m_{P_2Cl_5 }=239.2125gP_2Cl_5$

Explanation:

Hello there!

In this case, according to the reaction:

$4P+5Cl_2\rightarrow 2P_2Cl_5$

Thus, since there is a 4:2 mole ratio of P to P2Cl5 and the molar mass of the later is 239.2125 g/mol, we obtain the following mass as the produced one:

$m_{P_2Cl_5 }=2.00molP*\frac{2molP_2Cl_5}{4molP} *\frac{239.2125gP_2Cl_5 }{1molP_2Cl_5} \\\\m_{P_2Cl_5 }=239.2125gP_2Cl_5$

Regards!

5 0

3 years ago

Calculate the percent ionization of nitrous acid in a solution that is 0.311 M in nitrous acid (HNO2) and 0.189 M in potassium n

Alla [95]

HNO2 =====> H+ + NO2-
Initial concentration = 0.311
C = -x,x,x 
E = 0.311-x,x,x

KNO2 ====>K+ + NO2-
Initial concentration = 0.189 
C= -0.189,0.189,0.189 
E = 0,0.189,0.189

6 0

3 years ago