Electrons are free to move throughout metal substance, shared throughout so electricity and heat are conducted well
Answer:
Explanation:
You must convert 30 % (m/v) to a molar concentration.
Assume 1 L of solution.
1. Mass of NaOH
2. Moles of NaOH
3. Molar concentration of NaOH
4. Volume of NaOH
Now that you know the concentration, you can use the dilution formula .
to calculate the volume of stock solution.
Data:
c₁ = 7.50 mol·L⁻¹; V₁ = ?
c₂ = 0.1 mol·L⁻¹; V₂ = 250 mL
Calculations:
(a) Convert millilitres to litres
(b) Calculate the volume of dilute solution
160gof CO2×1molof CO2\44g of CO2×1mole of C\1mol of CO2×12g of C\1mole of C=
43.63g of C
Answer is: V<span>an't Hoff factor (i) for this solution is 2,26.
</span>Change in freezing point
from pure solvent to solution: ΔT =i · Kf · m.
<span>Kf - molal freezing-point depression constant for water is 1,86°C/m.
</span>m - molality, moles of solute per kilogram of solvent.
n(K₂SO₄) = 16,8 g ÷ 174,25 g/mol
n(K₂SO₄) = 0,096 mol.
m(K₂SO₄) = 0,096 mol/kg.
ΔT = 0,405°C.
i = 0,405 ÷ (1,86 · 0,096)
i = 2,26.
Answer:
A. Their numbers of atoms
Explanation: