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abruzzese [7]
3 years ago
15

A bacterial colony is grown in a laboratory under controlled conditions. Based on the data, we would expect the bacterial popula

tion to double in about ____ hours. A) 12 B) 15 C) 22.5 D) 30
Chemistry
2 answers:
Leto [7]3 years ago
8 0

bacterial population to double in about 15 hours

Alika [10]3 years ago
6 0

Answer:

A) 12 hours approximately

Duplication times vary depending on the microorganism in question.

Explanation:

Bacterial growth is the division of a bacterium into two daughter cells in a process called binary fission. Assuming that no case of mutation occurs, the resulting daughter cells will be genetically identical to the original cell. In this way the duplication of the bacterial population takes place.  The bacterial population experiences exponential growth.

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An atom is the smallest identifiable unit of a compound true or false
notsponge [240]
 False that  atom  is the smallest  identifiable  unit  of  a compound.

The   smallest   identifiable  unit  of   a compound  is  the    Element.  Element  is the one which  make up the  compound  and element  is made up by atoms.  Example  of element  is  oxygen  and  hydrogen  which  make  up water (H2O) which is  a compound.
7 0
3 years ago
An arctic weather balloon is filled with 27.8 L of helium gas inside a prep shed. The temperature inside the shed is . The ballo
Liula [17]

The question is incomplete, here is a complete question.

An arctic weather balloon is filled with 27.8 L of helium gas inside a prep shed. The temperature inside the shed is 13 ⁰C. The balloon is then taken outside, where the temperature is -9 ⁰C. Calculate the new volume of the balloon. You may assume the pressure on the balloon stays constant at exactly 1 atm. Be sure your answer has the correct number of significant digits.

Answer : The new volume of the balloon is 25.7 L

Explanation :

Charles's Law : It is defined as the volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

V\propto T

or,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1 = initial volume of gas = 27.8 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 13^oC=273+13=286K

T_2 = final temperature of gas = -9^oC=273+(-9)=264K

Now put all the given values in the above equation, we get:

\frac{27.8L}{286K}=\frac{V_2}{264K}

V_2=25.7L

Therefore, the new volume of the balloon is 25.7 L

3 0
3 years ago
Calculate the empirical formula the compound with the following percent composition: 27.59%C 1.15%H 16.09%N 55.17%O
jeyben [28]

Answer: C2HNO3

Explanation: C = 27.59/12.011 = 2.297

H = 1.15/1.008 = 1.1409

N = 16.09/14.007 = 1.1487

O = 55.17/15.999 = 3.4483

Divide by smallest result:

C = 2

H=1

N=1

O = 3

Empirical formula = C2HNO3

8 0
3 years ago
A chocolate bar weighs 4.00 ounces. If the chocolate delivers 2.78 calories per gram, how many
dimulka [17.4K]

Answer:

40.79

Explanation:

an ounce is equal to approximately 28.3 grams.

if you have 4 ounces then it would be equal to about 113.4 grams. then you would divide that by 2.78 which will equal about 40.8

6 0
3 years ago
The conversion of acetyl chloride to methyl acetate occurs via the following two-step mechanism: Reaction sequence of acetyl chl
Svetlanka [38]

If the concentration of acetyl chloride  is increased ten times the rate of reaction is increased ten times.

The conversion of acetyl chloride to methyl acetate is a substitution reaction. Recall that a substitution reaction is one in which a moiety in a molecule is replaced by another.

In this reaction, the CH3O- ion replaces the chloride ion. In the first step, the CH3O- ion attacks the substrate in a slow step. This creates a tetrahedral intermediate. Loss of the chloride ion yields the  methyl acetate product.

The rate determining step is the formation of the tetrahedral intermediate. Since the reaction is first order in the acetyl chloride, if its concentration is increased ten times the rate of reaction is increased ten times.

Learn more: brainly.com/question/5624100

4 0
3 years ago
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