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Ulleksa [173]
3 years ago
11

12p + 7 > 139 greater or less than

Mathematics
1 answer:
bazaltina [42]3 years ago
3 0

Answer:

\Huge \boxed{p>11}

Step-by-step explanation:

First, subtract by 7 both sides of equation.

\displaystyle 12p+7-7>139-7

Solve.

\displaystyle 139-7=132

12p>132

Then, divide by 12 both sides of equation.

\displaystyle \frac{12p}{12}=\frac{132}{12}

Solve to find the answer.

\displaystyle 132\div12=11

\huge \boxed{p>11}, which is our answer.

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Step-by-step explanation:

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Eggs are boxed in a crate. Each crate has 485 eggs. How many eggs are there in 525 ?
jok3333 [9.3K]

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aleksandrvk [35]
Easy peasy

the bit where it says
D={something}
those are the numbers you should input for x to get y values


3.
first solve for y to make life easier
-3x-5y=20
times -1
3x+5y=-20
minus 3x both sides
5y=-3x-20
divide both sides by 5
y=-3/5x-4
sub value of the domain
x=-10
y=-3/5(-10)-4
y=6-4
y=2
a point is (-10,2)

x=-5
y=-3/5(-5)-4
y=3-4
y=-1
(-5,-1) is another

x=0
y=-3/5(0)-4
y=-4
(0,-4) is another

x=5
y=-3/5(5)-4
y=-3-4
y=-7
(5,-7)

points are (-10,2), (-5,-1), (0,-4), (5,-7)



4.
input
x=-2
y=(-2)^2-3
y=4-3
y=1
(-2,1)

x=-1
y=(-1)^2-3
y=1-3
y=-2
(-1,-2)

x=0
y=(0)^2-3
y=-3
(0,-3)

x=1
y=(1)^2-3
y=1-3
y=-3
(1,-3)

x=2
y=(2)^2-3
y=4-3
y=1
(2,1)

the points are (-2,1), (-1,-2), (0,-3), (1,-2), (-2,1)

see graph below

5 0
3 years ago
What is the area of the rectangle? Show ALL your work! Do not round at any point!
faust18 [17]

First lets work out the length of the top side which joins the points (-1,7) and (-5,5):-

this =  sqrt ( (7-5)^2 + (-1 - (-5)^2 )

=  sqrt (4 + 16)

= sqrt 20

Now find length of the longer side which is distance between the points (-1,7) and (4, -3)

this is sqrt ( (-1 - 4)^2 +  (7 - -3)^2)

= sqrt  125

Area of the rectangle = sqrt 20 * sqrt 125

= sqrt 2500

= 50 units^2  Answer

6 0
3 years ago
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