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I am Lyosha [343]
3 years ago
6

A motorboat, that has speed of 10 km hour in still water, left a pier traveling against the current of the river. Forty-five min

utes after the boat left the pier, the motor of the boat broke, and the boat began drifting with the current. After three hours of drifting with the current, the boat was back at the pier where it had started. What is the speed of the current of the river?
Mathematics
1 answer:
Leokris [45]3 years ago
4 0

9514 1404 393

Answer:

  2 km/h

Step-by-step explanation:

  distance = speed × time

The boat's progress upriver can be modeled by ...

  (10 -c)(3/4) +(0 -c)(3) = 0

  7.5 -3.75c = 0 . . . . simplify

  2 -c = 0 . . . . . . . . . divide by 3.75

  c = 2 . . . . . . add c

The speed of the current is 2 km per hour.

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Step-by-step explanation:

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2 years ago
What is e-1/2f when e=15 and f=2
dusya [7]

Answer:

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Step-by-step explanation:

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3 years ago
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Really need help on my correction if anyone know please help!!
Olin [163]
Answers: 
<u>Question 19:</u> 177 bpm
<u>Question 20:</u> 95˚F

Explanations:
<u>Question 19:</u>
You had the formula set up properly like this:
R =  \frac{885 \sqrt{25} }{25}  =  \frac{885(5)}{25}  =  \frac{4425}{25} 
This is where you went wrong - I don't know exactly what you did, but your division of 4425 ÷ 25 is wrong. You should have ended up with 177 which is the correct answer. 
<u>Question 20:</u>
You had the formula set up correctly again, and merely used the wrong sign when adding 32. 
F =  \frac{9(35)}{5} + 32 =  \frac{315}{5} + 32
This is where you went wrong. You subtracted 32 from 63 when you should have added it. (See red circle on your subtraction.)
63 + 32 = 95˚F
7 0
3 years ago
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