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Advocard [28]
3 years ago
5

Solve the system of inequalities: 6y≥42 4y+12≤0

Mathematics
1 answer:
Hatshy [7]3 years ago
8 0

Answer:

no solution

Step-by-step explanation:

6y≥42

Divide each side by 6

6y/6≥42/6

y≥7

Then solve the second one

4y+12≤0

Subtract 12 from each side

4y+12-12≤0-12

4y ≤-12

Divide each side by 4

4y/4 ≤-12/4

y ≤-3

There is no solution since there is no overlap

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