Answer:
6750
Step-by-step explanation:
4 digit numbers are 1000,1001,1002,...,9999
let numbers=n
d=1001-1000=1
9999=1000+(n-1)1
9999-1000=n-1
8999+1=n
n=9000
now let us find the 4 digit numbers divisible by 4
4| 1000
______
| 250
4 |9999
_____
| 2499-3
9999-3=9996
so numbers are 1000,1004,1008,...,9996
a=1000
d=1004-1000=4
let N be number of terms
9996=1000+(N-1)4
9996-1000=(N-1)4
8996=(N-1)4
N-1=8996/4=2249
N=2249+1=2250
so number of 4 digit numbers not divisible by 4=9000-2250=6750
Answer:
k = 9
Step-by-step explanation:
n = 3, so substitute 3 for n in the equation
k = 3(3)
k = 9
May be there is an operator missing in the first function, h(x). I will solve this in two ways, 1) as if the h(x) = 5x and 2) as if h(x) = 5 + x
1) If h(x) = 5x and k(x) = 1/x
Then (k o h) (x) = k ( h(x) ) = k(5x) = 1/(5x)
2) If h(x) = 5 + x and k (x) = 1/x
Then (k o h)(x) =k ( h(x) ) = k (5+x) = 1 / [5 + x]
Sarah has 2 3/4 more meters of rope.
First you make them mixed numbers:
9/2 ÷ 19/8
Then you flip the second fraction around
9/2 ÷ 8/19
Then you change ÷ to ×
9/2 × 8/19
And then multiply across!
72/38 = 1 34/38 = 1 17/19 (the final answer)
Hope this helps!