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Brilliant_brown [7]
3 years ago
15

If R1 and R2 are the roots of x^2+4x-5=0

Mathematics
1 answer:
professor190 [17]3 years ago
3 0
Factor to find the roots.
(x+5)(x-1)=0

Proof:
5-1=4
5*-1=-5

Then apply the Zero Product Property.
(x+5)=0
x=-5

(x-1)=0
x=1

Roots: x=-5, x=1
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Select all expressions that represent a correct solution to the equation 6(x+4)=20
Sergeeva-Olga [200]

Answer:

D. 20 ÷ 6 − 4

E. 1/6(20 − 24)

F. (20−24) ÷ 6

Step-by-step explanation:

6(x + 4) = 20

6(x) + 6(4) = 20

6x + 24 = 20

     - 24  - 24

6x = -4

/6    /6

x = -4/6 or x = -2/3

D. 20 ÷ 6 − 4

20/6 - 4

20/6 - 24/6

-4/6 = -2/3

E. 1/6(20 − 24)

1/6(-4)

-4/6 = -2/3

F. (20 − 24) ÷ 6

- 4 / 6

-4/6 = -2/3

Hope this helps!

3 0
2 years ago
The circumference of a circular tabletop is 226. 08 inches. What is the area, in square inches, of the tabletop? *
Delicious77 [7]

Answer:

40,143.4 square inches

Step-by-step explanation:

c= 226.08

r= 113.04

area = Pi *r^2

3 0
2 years ago
What is −20÷45−20÷45 ?<br><br><br> A. −25<br><br> B. −16<br><br> C− 1/16<br><br> D. − 1/25
stealth61 [152]
The answer is -25 i just took the test/quiz
7 0
3 years ago
Fencing costs $10.15/ft. A customer purchases 8 3/8 ft of fencing for his yard. How much did the customer pay for the fencing? R
topjm [15]
The customer pays $85 because 10.15 multiplied by 8.375 equals 85.00625 or $85 hope that helps! 
4 0
3 years ago
In the right triangle ?ABC, leg AC=6 cm and leg BC=8 cm. Point M and N belong to AB so that AM:MN:NB=1:2.5:1.5. Find area of ?MN
Licemer1 [7]

Given : In Right triangle ABC, AC=6 cm, BC=8 cm.Point M and N belong to AB so that AM:MN:NB=1:2.5:1.5.

To find : Area (ΔMNC)

Solution: In Δ ABC, right angled at C,

AC= 6 cm, BC= 8 cm

Using pythagoras theorem

AB² =AC²+ BC²

      =6²+8²

     = 36 + 64

→AB²  =100

→AB²  =10²

 →AB  =10

Also, AM:MN:NB=1:2.5:1.5

Then AM, MN, NB are k, 2.5 k, 1.5 k.

→2.5 k + k+1.5 k= 10

→ 5 k =10

Dividing both sides by 2, we get

→ k =2

MN=2.5×2=5 cm, NB=1.5×2=3 cm, AM=2 cm

As Δ ACB and ΔMNC are similar by SAS.

So when triangles are similar , their sides are proportional and ratio of their areas is equal to square of their corresponding sides.

\frac{Ar(ACB)}{Ar(MNC)}=[\frac{10}{5}]^{2}

\frac{Ar(ACB)}{Ar(MNC)}=4

But Area (ΔACB)=1/2×6×8= 24 cm²[ACB is a right angled triangle]

\frac{24}{Ar(MNC)}=4

→ Area(ΔMNC)=24÷4

→Area(ΔMNC)=6 cm²

4 0
3 years ago
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