1) -12
ab is a times b. We plug in the numbers (-4)*(3) which equals -12.
2) 1
We plug in -4 for a, and 3 for b into the equation.
We get 2(-4) + 3(3)
2*-4 is -8. 3*3 is 9. We add them both, and -8+9 equals 1.
3) -14
We plug in -4 for a, and 3 for b into the equation.
2(-4-3)
-4-3 is -7. -7*2 equals -14.
Answer:
Step-by-step explanation:
Answer:
b
Step-by-step explanation:
Answer:
Type I error.
Step-by-step explanation:
Let's remember the definition of Type I error and Type II error:
A type I error is the rejection of a true null hypothesis, this means that we would get a "false positive" with this error.
A type II error is the non rejection of a not true null hypothesis, this error would give us a "false negative".
In this problem, we are told that the mean match score to identify a suspect is 80. However, the test shows that the mean match score is more than 80 when the person doesn't have a fingerprint match (and therefore the person would not be a suspect). Therefore, this person would appear as a suspect when he/she really isn't one. This means that the test is giving a "false positive". Thus, this is a type I error.
Answer:
Step-by-step explanation:
Given that A be the event that a randomly selected voter has a favorable view of a certain party’s senatorial candidate, and let B be the corresponding event for that party’s gubernatorial candidate.
Suppose that
P(A′) = .44, P(B′) = .57, and P(A ⋃ B) = .68
From the above we can find out
P(A) = 
P(B) = 
P(AUB) = 0.68 =
a) the probability that a randomly selected voter has a favorable view of both candidates=P(AB) = 0.30
b) the probability that a randomly selected voter has a favorable view of exactly one of these candidates
= P(A)-P(AB)+P(B)-P(AB)
c) the probability that a randomly selected voter has an unfavorable view of at least one of these candidates
=P(A'UB') = P(AB)'
=
