1. consider one angle of a (convex) heptagon. From that angle you can construct 7-3=4 diagonals. (-3 because we cannot create diagonals with the adjacent vertices and the angle itself )
2. 4 diagonals create 5 triangular regions. (check the picture)
3. So the sum of the measures of the interior angles of the heptagon is 180°*5=900°.
4. The measure of the remaining 7th interior angle is 900°-(120+150+135+170+90+125)°=110°.
5. The largest exterior angle is when the interior angle is the smallest.
6. The smallest interior angle is 90°, so the largest exterior angle is 180°-90°=90°
Answer: 90°
For this case, we have the following expression:

We simplify the expression:
If we add similar terms, taking into account that different signs are subtracted and the sign of the greater one is placed, we have that 
So, we have to:

Answer:
-3x + x + 5 = -2x + 5
<span>Slope of JK=((-1)-2)/(4-(-3)=-3/7
Slope of KL=((-5)-(-1)/(2-4=2
Slope of LM=((-2)-(-5))/(-5-2)=-3/7
Slope of MJ=(2-(-2))/((-3)-(-5))= 2
JK is parallel to LM and KL is parallel to MJ. Therefore JKLM is a parallelogram.</span>
Answer:
2.25π square inches [or 7.07 sq. in. rounded to 2 decimal places]
Step-by-step explanation:
The largest circle inscribed in a square would have DIAMETER EQUAL TO THE SIDE LENGTH OF THE SQUARE.
Since diameter is double of radius, we can find the radius to be:
diameter = 3 [side length of square]
radius = 3/2 = 1.5 inches
The area of a circle is πr^2
THus, the largest circle area = πr^2 = π(1.5)^2 = π(2.25) = 2.25π square inches
.438
rounded to nearest tenth = .4
rounded to nearest hundredth = .44