Var[2X + 3Y] = 2² Var[X] + 2 Cov[X, Y] + 3² Var[Y]
but since X and Y are given to be independent, the covariance term vanishes and you're left with
Var[2X + 3Y] = 4 Var[X] + 9 Var[Y]
X follows an exponential distribution with parameter <em>λ</em> = 1/6, so its mean is 1/<em>λ</em> = 6 and its variance is 1/<em>λ</em>² = 36.
Y is uniformly distributed over [<em>a</em>, <em>b</em>] = [4, 10], so its mean is (<em>a</em> + <em>b</em>)/2 = 7 and its variance is (<em>b</em> - <em>a</em>)²/12 = 3.
So you have
Var[2X + 3Y] = 4 × 36 + 9 × 3 = 171
Answer is <span>a.) -16j2k
hope it helps</span>
Answer:
Crayola Classic: 5 Packs; Crayola Tropical: 4 Packs
Step-by-step explanation:
Keep multiplying by both until you get a number equal to eachother
1. 8 x 2 = 16, 10 x 2 = 20
2. 8 x 3 = 24, 10 x 3 = 30
You may notice that the numbers are getting farther apart. This is normal because the boxes are not equal and are getting multiplied further. That means that your answer will have different factors in both the equations.
3. 8 x 4 = 32, 10 x 4 = 40
4. 8 x 5 = 40
Both of those equations (in bold) have the same answer and he wanted the same crayons from both. So, the answer is:
10 x 4 = 40
8 x 5 = 40
(how much packs of each you need to get the same amount)
Hope this helps :)
-jp524
Three times (3 times something) the difference of x and 2 (2-x) is greater than (>) -21 (-21)
3 times (2-x)>-21
3(2-x)>-21
distrobite using distributiver poerpoty
a(b+c)=ab+ac
3(2-x)=6+(-3x)=6-3x
6-3x>-21
add 3x to both sides
6>-21+3x
add 21 to both sides
27>3x
divide both sides by 3
9>x
x<9
so x= any number below 9 not including 9
A
E
H
all have the same vale of 81