Answer:
19%
Step-by-step explanation:
Last year:
Number of boys on honor roll = 96
Number of girls on honor roll = 60
Total students on honor roll = Number of boys on honor roll + Number of girls on honor roll
= 96 + 60
= 156
This year:
The number of boys on the honor roll increased by 25%
Number of boys on honor roll = 25% of 96 + 96
= 0.25×96 + 96
= 24 + 96
= 120
The number of girls on the honor roll increased by 10%.
Number of girls on honor roll = 10% of 60 + 60
= 0.10 × 60 + 60
= 6 + 60
= 66
Total students on honor roll = Number of boys on honor roll + Number of girls on honor roll
= 120 + 66
= 186
Percentage the total number of students on the honor roll increase = (186 - 156) / 156 × 100
= 30 / 156 × 100
= 0.19 × 100
= 19% to the nearest tenth
From the given f(x) and g(x), the value of (g-f)(2)=1
Given :
The functions are

Lets evaluate (g-f)(2)

To find out g(2), replace 2 for x in g(x) and then replace 2 for x in f(x)

Now we find g(2)-f(2)

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Multiple: 4 * 1
/2 = 4 · 1 = 4
/2 = 2 · 2
1 · 2 1 · 2 = 2
Multiply both numerators and denominators. Result fraction keep to lowest possible denominator GCD(4, 2) = 2
Multiple: 7 * 2 = 14
Multiple: 5 * 1
/3 = 5 · 1
1 · 3 = 5
/3
Multiply both numerators and denominators. Result fraction keep to lowest possible denominator GCD(5, 3) = 1
Multiple: 3 * 5
/3 = 3 · 5
1 · 3 = 15
/3 = 5 · 3
1 · 3 = 5
Multiply both numerators and denominators. Result fraction keep to lowest possible denominator GCD(15, 3) = 3
Add: 14 + 5 = 19
Multiple: -3 * 1
/2 = -3 · 1
1 · 2 = -3
/2
= -1.5 · 2
1 · 2
Multiply both numerators and denominators. Result fraction keep to lowest possible denominator GCD(-3, 2) = 2
Multiple: 1/2 * (-3
/2
) = 2 · (-3)
1 · 2 = -6
/2 = -3 · 2
1 · 2 = -3
Multiply both numerators and denominators. Result fraction keep to lowest possible denominator GCD(-6, 2) = 2
Add: 19 + (-3) = 16
7(4×1/2) + 3(5×1/3) + 2(-3×1/2) = 16
/1 = 16
Answer:
it is sin C
Step-by-step explanation: