Given:
side length = 6 ft
To find:
The area of the figure
Solution:
Area of the square = side × side
= 6 × 6
Area of the square = 36 ft²
Diameter of the semi-circle = 6 ft
Radius of the semi-circle = 6 ÷ 2 = 3 ft
Area of the semi-circle = 
Area of the semi-circle = 14.13 ft²
Area of the figure = Area of the square - Area of the semi-circle
= 36 ft² - 14.13 ft²
= 21.87 ft²
Area of the figure = 21.9 ft²
The area of the figure is 21.9 ft².
Answer:
1.66667
Step-by-step explanation:
9------1
15-----?
We divide 9 by 9 to get 1 so we divide 15 by 9 to get ?
15 / 9 = 1.66667
a. The difference between two outputs that are 1 unit apart.
You need to Use y2 - y1 / x2 - x1 to find the difference
I will choose x2 as 1 and x1 as 0
(29 - 21) / (1 - 0)
8/1 so The difference is 8 per 1 unit.
b. Use the same formula
I will choose -3 as x2 and -5 as x1
(5 - (-11)) / (-3 - (-5))
(5 + 11) / (-3 + 5)
16 / 2 so the difference is 16 per 2 units.
c. I will choose 2 as x2 and -1 as x1
(45 - 21) / (2 - (-1))
24/3 so the difference is 24 per 3 units.
d. The ratios of the differences to the input intervals reduced all equal each-other, which is 8 per 1 unit.
( -3,4 ) let me know if you need an extension
