Ask question

Ask question

All categories

3 years ago

9

Each of 5 birdwatchers reported seeing 15 roseate spoonbills in a day. If they each reported seeing the same nunber of roseate s

poonbills over 14 days, how many would be reported?

1 answer:

LuckyWell [14K]3 years ago

4 0

Each of the 5 saw 15 birds a day, so they saw 75 each day for 14 days. 75 times 14 is 1,050. They saw in total, 1,050 birds.

You might be interested in

Thomas bought 4 shirts from a store. The price of each shirt was the same. After he bought the shirts, his account balance showe

ludmilkaskok [199]

$89.08 divided by 4 is $22.27, aka the price of one shirt

8 0

3 years ago

Read 2 more answers

Which value is equivalent to ( 7 • 5 • 2 over 7 • 3) ^2 • ( 5^0 over 2^-3) ^3 • 2^-9

ser-zykov [4K]

100 / 9

They both equal 11.11
(70/21)^2 * 8^3 * (1/2^9)

3 0

3 years ago

Please help last question:((

jasenka [17]

Answer:

7. C(N(h))=33hx+460h

8. about $13.94 is the cost

Step-by-step explanation:

7. C(x)=(33x+460)(N(h))=(N(40)h)--C(x)=(33x+460)(40h)--C(x)=1320hx+18400h--simplified to C(N(h))=33hx+460h

8. C(N(10))=33(10)x+460(10)--C(N(10))=330x+4600--4600/330=about13.94

5 0

3 years ago

sThe number of users on a social networking site was 45 thousand in February when theyofficially went public, and grew to 60 tho

svetoff [14.1K]

Given:

No of users in February is 45,000 and in october its 60,000.

$P=45000(\frac{4}{3})^{(\frac{3}{2})^t}$

t=2

$P=45000(\frac{4}{3})^3$ $P=45000(\frac{64}{27})$ $P=5000(\frac{64}{3})$ $P=106666.6667$

Therefore, approximate no of users after 2 years is 106667.

6 0

1 year ago

What was the original price of the tv? Show two methods for finding your answer

dusya [7]

Answer: Any pictures or more information?

Step-by-step explanation: Really happy to help you

6 0

3 years ago