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gizmo_the_mogwai [7]
3 years ago
8

Which value is equivalent to ( 7 • 5 • 2 over 7 • 3) ^2 • ( 5^0 over 2^-3) ^3 • 2^-9

Mathematics
1 answer:
ser-zykov [4K]3 years ago
3 0
100 / 9

They both equal 11.11
(70/21)^2 * 8^3 * (1/2^9)
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How to answer <br> 100x^2+60x+9
iVinArrow [24]

Answer:

Step-by-step explanation:

Rewrite

100

x

2

100

x

2

as

(

10

x

)

2

(

10

x

)

2

.

(

10

x

)

2

+

60

x

+

9

(

10

x

)

2

+

60

x

+

9

Rewrite

9

9

as

3

2

3

2

.

(

10

x

)

2

+

60

x

+

3

2

(

10

x

)

2

+

60

x

+

3

2

Check the middle term by multiplying

2

a

b

2

a

b

and compare this result with the middle term in the original expression.

2

a

b

=

2

⋅

(

10

x

)

⋅

3

2

a

b

=

2

⋅

(

10

x

)

⋅

3

Simplify.

2

a

b

=

60

x

2

a

b

=

60

x

Factor using the perfect square trinomial rule

a

2

+

2

a

b

+

b

2

=

(

a

+

b

)

2

a

2

+

2

a

b

+

b

2

=

(

a

+

b

)

2

, where

a

=

10

x

a

=

10

x

and

b

=

3

b

=

3

.

(

10

x

+

3

)

2

3 0
3 years ago
Cos (90-theta) • cosec90-theta) =tano. How?​
denis-greek [22]

Answer:

<u>______________________________________________________</u>

<u>TRIGONOMETRY IDENTITIES TO BE USED IN THE QUESTION :-</u>

For any right angled triangle with one angle α ,

  • \cos (90 - \alpha  ) = \sin \alpha  or  \sin(90 - \alpha ) = \cos\alpha
  • cosec \: (90 - \alpha  ) = \sec\alpha   or  \sec(90 - \alpha ) = cosec\:\alpha

<u>SOME GENERAL TRIGNOMETRIC FORMULAS :-</u>

  • <u></u>\sin \alpha = \frac{1}{cosec \: \alpha }  or  cosec \: \alpha  = \frac{1}{\sin \alpha }
  • <u></u>\cos \alpha = \frac{1}{\sec \alpha }  or  \sec \alpha = \frac{1}{\cos \alpha }

<u>______________________________________________________</u>

Now , lets come to the question.

In a right angled triangle , let one angle be α (in place of theta) .

So , lets solve L.H.S.

\cos (90 - \alpha ) \times cosec(90 - \alpha )

=> sin\alpha  \times \sec\alpha

=> \sin\alpha  \times \frac{1}{\cos\alpha }

=> \frac{\sin\alpha }{\cos\alpha }

=> \tan\alpha = R.H.S.

∴ L.H.S. = R.H.S. (Proved)

3 0
3 years ago
51pts! What is the factored form of this expression? 6x^2+5x-6=(_______)(______)
notsponge [240]
It should be (2x-3)x(3x+2)
4 0
3 years ago
Which equation is not equivalent to the other two
Liula [17]

Answer:

y=-4-3x

Step-by-step explanation:

y = -3x - 4

y = -3x + (-4)

y = -4 + 3x

y = -4 - 3x

7 0
3 years ago
Are these parallel, perpendicular, or neither?
Elina [12.6K]
Answer: I think it’s neither

Explanation:

The line is parallel unless the slope is the same and with a different y-intercept

The line are perpendicular unless the one of the slope is the negative reciprocal of the other.

And both equation didn’t meet any of the requirement.
5 0
3 years ago
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