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bazaltina [42]
3 years ago
7

Round this number to the nearest 100 38288

Mathematics
2 answers:
N76 [4]3 years ago
8 0
The answer to this is 38300 hope this helped
ddd [48]3 years ago
3 0
38,300

the 2 last digits are over 50. which indicates to round up.

Hope this helps!
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Determine whether each expression is equivalent to 49^2t – 0.5.
vampirchik [111]

Answer:

None of the expression are equivalent to 49^{(2t - 0.5)}

Step-by-step explanation:

Given

49^{(2t - 0.5)}

Required

Find its equivalents

We start by expanding the given expression

49^{(2t - 0.5)}

Expand 49

(7^2)^{(2t - 0.5)}

7^2^{(2t - 0.5)}

Using laws of indices: (a^m)^n = a^{mn}

7^{(2*2t - 2*0.5)}

7^{(4t - 1)}

This implies that; each of the following options A,B and C must be equivalent to 49^{(2t - 0.5)} or alternatively, 7^{(4t - 1)}

A. \frac{7^{2t}}{49^{0.5}}

Using law of indices which states;

a^{mn} = (a^m)^n

Applying this law to the numerator; we have

\frac{(7^{2})^{t}}{49^{0.5}}

Expand expression in bracket

\frac{(7 * 7)^{t}}{49^{0.5}}

\frac{49^{t}}{49^{0.5}}

Also; Using law of indices which states;

\frac{a^{m}}{a^n} = a^{m-n}

\frac{49^{t}}{49^{0.5}} becomes

49^{t-0.5}}

This is not equivalent to 49^{(2t - 0.5)}

B. \frac{49^{2t}}{7^{0.5}}

Expand numerator

\frac{(7*7)^{2t}}{7^{0.5}}

\frac{(7^2)^{2t}}{7^{0.5}}

Using law of indices which states;

(a^m)^n = a^{mn}

Applying this law to the numerator; we have

\frac{7^{2*2t}}{7^{0.5}}

\frac{7^{4t}}{7^{0.5}}

Also; Using law of indices which states;

\frac{a^{m}}{a^n} = a^{m-n}

\frac{7^{4t}}{7^{0.5}} = 7^{4t - 0.5}

This is also not equivalent to 49^{(2t - 0.5)}

C. 7^{2t}\ *\ 49^{0.5}

7^{2t}\ *\ (7^2)^{0.5}

7^{2t}\ *\ 7^{2*0.5}

7^{2t}\ *\ 7^{1}

Using law of indices which states;

a^m*a^n = a^{m+n}

7^{2t+ 1}

This is also not equivalent to 49^{(2t - 0.5)}

6 0
3 years ago
The leg of a right triangle is 3 units and the hypotenuse is 11 units. What is the length, in units, of the other leg of the tri
son4ous [18]

Answer:

D

Step-by-step explanation:

8 0
3 years ago
Write any 4 laws of exponents.<br>​
emmainna [20.7K]

         \rule{50}{1}\large\blue\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}

       <em>Write any 4 laws, or properties, of exponents.</em>

<em />

<em>        </em>\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}

\Large\text{Law number 1:-}

\Large\text{$a^n*a^m=a^{n+m}$}

\Large\text{It states that:-}

                        When we multiply together numbers with the same base,

                         we add the exponents.

\Large\text{Law number 2:-}

\Large\text{$a^m:a^n=a^{m-n}$}

\Large\text{It states that:-}

                     When we divide numbers with the same base, we

                     subtract the exponents.

\Large\text{Law number 3:-}

\Large\text{$(\displaystyle\frac{x}{y}) ^n=\frac{x^n}{y^n}$}

\Large\text{It states that:-}

                 If we have a fraction to a power, we raise the numerator and

               the denominator to that power.

And then last but not least,

\Large\textit{Law number 4:-}

\Large\text{$a^{-m} =\displaystyle\frac{1}{a^m}$}

\Large\text{It states that:-}

                   If we have a number with a negative exponent, we flip it over.

<h3>Good luck with your studies.</h3>

#TogetherWeGoFar

\rule{50}{1}\smile\smile\smile\smile\smile\smile\rule{50}{1}

6 0
2 years ago
Read 2 more answers
Solve 6 1/2 + 7 3/8 - 6 1/2
Amiraneli [1.4K]

Answer:

Step-by-step explanation:

6 1/2 - 6 1/2 + 7 3/8 =

0 + 7 3/8 = 7 3/8

3 0
3 years ago
Rewrite the following equation as a function of x.<br><br> 43 - 1/8y + 19 = 0
tamaranim1 [39]

Answer:

y = 496

Step-by-step explanation:

62 - 1/8y = 0

8 (62 - 1/8y ) = 8×0

496 - y = 0

496 = y

y = 496

5 0
3 years ago
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