Find the sum of the sequence. 45+46+47+48+...+108
2 answers:
We know, S = n/2 [ a + l ]
Here, a = 45
l = 108
Calculation of n:
a(n) = a + (n - 1)d
108 = 45 + (n - 1)1
108 - 45 = n - 1
63 + 1 = n
n = 64
Now, substitute in the expression:
S = 64/2 [ 45 + 108 ]
S = 32 [ 153 ]
S = 4896
In short, Your Answer would be 4896
Hope this helps!
The Total sum of the mentioned series is 4896
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