Find the sum of the sequence. 45+46+47+48+...+108

2 answers:

7 0

We know, S = n/2 [ a + l ]
Here, a = 45
l = 108

Calculation of n:
a(n) = a + (n - 1)d
108 = 45 + (n - 1)1
108 - 45 = n - 1
63 + 1 = n
n = 64

Now, substitute in the expression:
S = 64/2 [ 45 + 108 ]
S = 32 [ 153 ]
S = 4896

In short, Your Answer would be 4896

Hope this helps!

OLga [1]3 years ago

6 0

The Total sum of the mentioned series is 4896

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so hmm if you notice, your f(x) there, looks just like g(x), but is "shifted horizontally" by about 9 units to the right

that simply means, based on that template above, that C/B = -9, and we can simply make B = 1 and C = -9, and we get C/B = -9/1 which is -9

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