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3 years ago

Find the sum of the sequence. 45+46+47+48+...+108

2 answers:

7 0

We know, S = n/2 [ a + l ]
Here, a = 45
l = 108

Calculation of n:
a(n) = a + (n - 1)d
108 = 45 + (n - 1)1
108 - 45 = n - 1
63 + 1 = n
n = 64

Now, substitute in the expression:
S = 64/2 [ 45 + 108 ]
S = 32 [ 153 ]
S = 4896

In short, Your Answer would be 4896

Hope this helps!

OLga [1]3 years ago

6 0

The Total sum of the mentioned series is 4896

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Solve for X y and z brainliest Round to nearest tenth

kykrilka [37]

Answer:

x=1

Z=35.4965

assuming you want y to be the height, y=5.916

Step-by-step explanation:

x/height=height/35

35x=y^2

using Pythagorean theorem

y^2+x^2=6^2

y^2+35^2=z^2

substituting for y^2

35x+x^2=6^2

x^2+35x-36=0

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y^2+x^2=6^2

substitute

y^2+1=36

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2 years ago

According to a study done by a university student, the probability a randomly selected individual will not cover his or her mou

Igoryamba

Answer: kindly check explanation

Step-by-step explanation:

Probability of not covering mouth = p(success) = 0.267

Hence, p(covering mouth) = 1 - 0.267 = 0.733

a) What is the probability that among 12 randomly observed individuals exactly 8 do not cover their mouth when sneezing?

Number of samples (n) = 12

P(X = 8)

Using binomial distribution :

P(x) = nCx * p^x * (1-p)^(n-x)

P(x =8) = 12C8 * 0.267^8 * 0.733^(12-8)

P(x =8) = 12C8 * 0.267^8 * 0.733^4

= 0.00369

b) What is the probability that among 12 randomly observed individuals fewer than 6 do not cover their mouth when sneezing?

P(X < 6) = p(5) + p(4) + p(3) + p(2) + p(1) + p(0)

To save computation time, we can use an online binomial probability calculator :

P(X < 6) = 0.9275

C.) Yes, I will be surprised, because from the binomial probability obtained above, there is a high probability (0.9275) that fewer than half do not cover their mouth.

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3 years ago

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Answer:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=0$

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Assuming the correct expression is to find the following limit:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}$

Use the property the limit of the quotient is the quotient of the limits:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}$

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Evaluate the denominator:

Since $\lim_{x \to1}sin(x-2)\neq 0$

$\frac{0}{\lim_{x \to1}sin(x-2)}=0$

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3 years ago

Can someone explain me how to solve this?

sesenic [268]

Answer:

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Step-by-step explanation:

since it is an isosceles triangle opposite sides are congruent which means 7x+24=13x-48 you then would need to subtract either the whole numbers or the variables from each side so add 48 on each side it equals to 7x+72=13x then subtract 7x from 13x and you get 72=6x divide both sides 6/6=x, 72/6 Therefore x=12 HOPE that helped mark me brainiest pls

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