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Natasha_Volkova [10]
3 years ago
7

Graph the linear function in questions 5 and 6. y=1/3x-4

Mathematics
1 answer:
goldfiish [28.3K]3 years ago
6 0

Answer:

For y = 1/3x - 4

Step-by-step explanation:


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Anon25 [30]

Answer:

2.17

Answer and Explanation:

The critical value of z for 97% confidence interval is 2.17, which is obtained by using a z score table, that is: {eq}P(-2.17 < Z <...

5 0
3 years ago
According to the Centers for Disease control and prevention, 20.8 of high school students currently use electronic cigarettes. A
Setler79 [48]

Answer:

H0 : p = 0.028

H1: p > 0.028

We conclude that there is not enough evidence to support the school counselor's claim they the use of electronic cigarettes in high school is higher Than 2.8%

Type 11 error

Step-by-step explanation:

H0 : p = 0.028

H1: p > 0.028

If null should not be rejected then;

We conclude that there is not enough evidence to support the school counselor's claim they the use of electronic cigarettes in high school is higher Than 2.8%

3.)

If the actual proportion is 0.034, which means 3.4%, this means it is actually higher. For failing to reject a false Null, then a type 11 error has been committed

6 0
3 years ago
Write the standard form of the equation of the circle with endpoints of a diameter at the points (7,2) and (-9,5).
lys-0071 [83]

Answer:

(x+1)^2 + (y- 3.5)^2 =64

Step-by-step explanation:

We are given that  endpoints of a diameter at the points (7,2) and (-9,5).

Center of the circle is the mid point of diameter

So, first find the mid point of diameter

Formula : x=\frac{x_1+x_2}{2} , y=\frac{y_1+y_2}{2}

(x_1,y_1)=(7,2)\\(y_1,y_2)=(-9,5)

Substitute the values in formula

x=\frac{7-9}{2} , y=\frac{2+5}{2}

x=-1 , y=3.5

So, center of circle = (h,k )=(-1,3.5)

To find length of diameter :

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

(x_1,y_1)=(7,2)\\(y_1,y_2)=(-9,5)

d=\sqrt{(-9-7)^2+(5-2)^2}

d=\sqrt{265}

Length of radius = r = \frac{Diameter}{2}=\frac{\sqrt{256}}{2}

Standard form of the equation of the circle : (x -h)^2 + (y- k)^2 = r^2

(h,k )=(-1,3.5)

r=\frac{\sqrt{256}}{2}

Equation of the circle : (x+1)^2 + (y- 3.5)^2 =(\frac{\sqrt{256}}{2})^2

Equation of the circle : (x+1)^2 + (y- 3.5)^2 =64

Hence  the standard form of the equation of the circle with endpoints of a diameter at the points (7,2) and (-9,5) is  (x+1)^2 + (y- 3.5)^2 =64

5 0
4 years ago
Can u help me please?????
GenaCL600 [577]

Answer:

the last one

Step-by-step explanation:

it is the one which is the most fair and would make sense, I don't exactly know how to explain it sorry

8 0
3 years ago
The value 3 is an upper bound for the zeros of the function shown below.
Sedaia [141]
It's FALSE just had the question.
8 0
3 years ago
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