All categories

3 years ago

\You want to find out the favorite subjects of students at your school. Which plan describes a good sample?

2 answers:

8 0

I believe the correct answer would be A.

I assume this because compared to the other given options, this method would target the most diverse audience.

Leni [432]3 years ago

4 0

Sample A will be a good choice.

It has students from all classes and all subjects.

All other options don't guarantee that they have students from all possible subjects.

You might be interested in

PLEASE HELP! The table shows the number of championships won by the baseball and softball leagues of three youth baseball divisi

Irina18 [472]

Answer:

Question 1: $P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16}}{ \frac{4}{16}} = \frac{1}{2}$

Question 2:

A. $P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

B. $P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

C. $P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

Step-by-step explanation:

Conditional probability is defined by

$P(A|B)= \frac{P(A and B)}{P(B)}$

with P(A and B) beeing the probability of both events occurring simultaneously.

Question 1:

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16} }{ \frac{4}{16} } = \frac{1}{2}$

Question 2.A:

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

Question 2.B:

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( Z and B)= \frac{ 1 }{ 16 }[/tex]

By definition,

$P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

Question 3.B

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

then

$P (Y or Z) = P(Y) + P(Z) = \frac{6}{16}$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

$P((YorZ) and B)= \frac{3}{16}$

By definition,

$P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

3 0

3 years ago

Evaluate f(x) = –x2 – 4 for x = –3.

melisa1 [442]

The answer to your problem is 2

6 0

3 years ago

Read 2 more answers

Help me please!!!!!!!!!!!

mamaluj [8]

The answer would be D Because one side is 18 and another is 26 and 18 times 26 is 468.

5 0

3 years ago

Read 2 more answers

Jamie is x years old. His friend Ana is the same age. Enter and expression in the box to represent the sum of Jamie and Ana ages

Lubov Fominskaja [6]

If Jamie's age is represented as x and given that Ana is the same age as Jamie then, Ana's age can also be represented by x. The sum of their ages is equal to,

Sum of their ages = x + x

Simplifying,

Sum of their ages = 2x

4 0

3 years ago

Read 2 more answers

800 shared into the ratio of 9:13:18

9966 [12]

Ratio 9:13:18......added = 40. This means that one person gets 9/40 of the total, one person gets 13/40 of the total and one person gets 18/40 of the total.

and if the total is 800...

9/40 * 800 = 7200/40 = 180 <==
13/40 * 800 = 10400/40 = 260 <==
18/40 * 800 = 14400/40 = 360 <==

4 0

2 years ago