Given P(A) = 0.072, P(B) = 0.180, and P(C) = 0.027, and that events A, B, and C are mutually exclusive,then P(A or B or C) is 0.279
<u>Solution:
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Given that probability of event A is P(A) = 0.072
Probability of event B is P(B) = 0.180
Probability of event C is P(C) = 0.027
Also event A, B and C are mutually exclusive.
Need to determine P( A or B or C )
For mutually exclusive events
P( A or B or C ) = P(A) + P(B) + P(C)
= 0.072 + 0.180 + 0.027 = 0.279
Hence probability of occurrence of event A or event B or event C , where A , B and C are mutually exclusive events is 0.279.
Answer:
a) 0.75
b) 0.0625
c) 0.1875
d) 0.375
Step-by-step explanation:
Let's start by first finding the probability a teacher orders 6 boxes. Since it is a four sided dice, the probability of getting a 1 is going to be 0.25.
Similarly, for any other number on the dice, the teacher orders 2 boxes. We can think of this as NOT rolling a 1. Using our previous answer, this comes out to be: 1 - 0.25 = 0.75
It should be remembered in the following answers that teachers ordering 6 or 2 boxes are not influenced by the results of other teachers. These are statistically independent events.
a) As given above, this probability is 0.75
b) The probability that both teachers order 6 boxes will be their individual probabilities multiplied. This comes out to be: 0.25 x 0.25 = 0.0625
c) Like in part (b), this is both of their probabilities multiplied:
0.25 x 0.75 = 0.1875
d) This is nearly the same as part (c), but with a little twist. The order matters. There are two scenarios:
- First teacher gets 6 boxes, and the second gets 2.
- First teacher gets 2 boxes, and the second gets 2.
Both of these events have a probability of 0.1875, as shown in (c). To get the total probability of this event happening, we must add these together:
0.1875 + 0.1875 = 0.375
Answer:
y=(2/3)x-1
Step-by-step explanation:
The slope is (1-(-1))/(3-0) = 2/3
And the y intercept is -1,
Therefore: y=(2/3)x-1
3m 15 m 6 m not dion to scale and find voulume I’d the triangular 4. 90 m3
Answer:
6 poinnts per question
Step-by-step explanation:
