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goldfiish [28.3K]
3 years ago
12

Hey what's

mes 2" alt=" \sqrt{169} \times 2" align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
elena-s [515]3 years ago
7 0
13 and the square root of 2
WITCHER [35]3 years ago
4 0

Answer:

the square root of 169 is 13 then ×2

26

I hope I am correct mate

enjoy your day

#Captainpower

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I need a Tutor and Help with this question
valkas [14]

Answer:

x=31

y=6

Step-by-step explanation:

2x+3y=80

x+y=37

solve by elimination:( multiply second equation by 2) to eliminate x

2x+3y=80

2x+2y=74

subtract the two equations:

2x+3y-(3x+2y)=80-74

2x+3y-3x-2y=6

y=6 (3 point basket)

substitute: x+y=37, x=37-6=31

x=31 (2 point shot)

4 0
3 years ago
Read 2 more answers
I need help pleaseeeee this is due tomorrow
sveta [45]

Another way of finding Surface Area is

  1. SA= 2LW+2LH+2HW

L= Length

W= Width

H= Height

the answer, and explained, would be this

2. SA= 2(12)(10)+2(12)(16)+2 (10)(16)

(<em>multiply</em>)

3. SA= 240 + 384 + 320

(<em>add</em>)

<em>The</em><em> </em><em>answer</em><em> </em><em>is</em><em>.</em><em>.</em><em> </em>

<em><u>SA</u></em><em><u>=</u></em><em><u>944ft3</u></em><em><u> </u></em>

7 0
3 years ago
Can u please help me on this problem
xxMikexx [17]
Any line is 180 degrees, so z is 67 degrees and x is 6.
7 0
4 years ago
The total mass of two packets of fruit is 10.5 kg. One packet of fruit is 3 kg lighter than the other. Find the mass of the heav
Ainat [17]
(3+x)+x=10.5

Simplify

2x = 7.5

x = 3.75

Plug in for x

(3 + 3.75) + 3.75 = 10.5

6.75 + 3.75 = 10.5

The heavier packet of fruit is 6.75 kg.
4 0
4 years ago
Lionel computed the average rate of change in the depth of a pool over a two-week interval to be zero. Which statement must be t
gayaneshka [121]

Answer:The pool must have been the same depth at the start of the interval as it was at the end of the interval.

Step-by-step explanation:

The average rate of change is calculated as:

[final value - initial value] / time interval.

Then, the average rate of change does not take into account intermediates values, and you cannot draw any conclusion about such intermediate values.

In the given case you have:

average rate of change in depth = [final depth - initial depth] / 2 weeks.

0 = [final depth - initial depth] / 2 weeks.

⇒ 0 = final depth - initial depth

⇒ final depth = initial depth.

That is why the conclusion is the second statement of the answer choices: the pool must have been the same depth at the start of the interval as it was at the end of the interval.

In between the pool might have been deeper, more shallow, empty or change in any form, since the average rate of change does not tell the full history but only the net change.

4 0
3 years ago
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