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Archy [21]
3 years ago
5

Rene is going to the lake to visit some friends. If the lake is 60 miles away and Rene is driving at 40 miles per hour the entir

e time, how long will it take her to get there?
Mathematics
1 answer:
MArishka [77]3 years ago
5 0

It will take her an hour and a hlaf

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How many 1/10's are in 2/5?
goblinko [34]
There is 4 1/10's in 2/5.

You do this by turning 2/5 into a fraction with a denominator of 10, so it will be 4/10. 1/10 + 1/10 + 1/10 + 1/10 = 4/10
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24 miles in T hours, 32 miles in T hours
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Round 253.5198 to the nearest thousandth
kipiarov [429]

Answer:

253.520

Step-by-step explanation:

Let us see what is the thousandths place...

It is the third digit to the right.

253.5198 rounded is about

253.520.

I can tell because you take the thousandths place, look at the one to the right of it, then if it is greater than 5, you make the thousandths place greater. Since it's a 9, you move the extra 10 thousandths to the next thing- the hundredths. and you get 253.520.

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3x - 3y = -15<br> -x + y = 5
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Answer:

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4 0
3 years ago
The U.S. Department of Housing and Urban Development publishes data on the fair market monthly rent for existing one-bedroom hou
Aleksandr [31]

Answer:

n=(\frac{1.960(80)}{25})^2 =246.73 \approx 247

So the answer for this case would be n=247 rounded up to the nearest integer

Step-by-step explanation:

We know that the standard deviation is :

\sigma = 80 represent the deviation

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =25 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution and the critical value would be z_{\alpha/2}=1.960, replacing into formula (b) we got:

n=(\frac{1.960(80)}{25})^2 =246.73 \approx 247

So the answer for this case would be n=247 rounded up to the nearest integer

8 0
3 years ago
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