I really need help anyone please

Mathematics

1 answer:

icang [17]3 years ago

4 0

(15x^3y^-8)÷(5x^2y^-4)
= 3xy^-4

(3x)/ y^4

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Before you can make a pie chart you need to figure out how much of the circle belongs to each category. Suppose that you earned

svetoff [14.1K]

Answer:

missions-24

recreation-108

savings-144

school supplies-48

tithe-36

Step-by-step explanation:

so first convert all the given costs to cents by multiplying each amount with 100 then add all of them to get the total as 600

in a pie chart we know that it's a circle and all angles within the circle must add up to 360 so to get an angle for a certain cost that will represent it in the chart you have to take that cost over the total to get the fraction of the circle it will occupy multiplied by 360 to get it in degrees or which portion of 360 will it occupy hence

60/600×360=36

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2 years ago

NASA launches a rocket at t=0 seconds. Its height, in meters above sea-level, as a function of time is given by h(t)=−4.9t2+121t

Alenkasestr [34]

NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by

$h(t)=-4.9t^2+121t+283$

The sea level is represented by h = 0, therefore, to find the corresponding time when h splashes into the ocean we have to solve for t the following equation:

$h(t)=0\implies-4.9t^2+121t+283=0$

Using the quadratic formula, the solution for our problem is

$\begin{gathered} t=\frac{-(121)\pm\sqrt{(121)^2-4(-4.9)(283)}}{2(-4.9)} \\ =\frac{121\pm142.083778...}{9.8} \\ =\frac{121+142.083778...}{9.8} \\ =26.8452834694... \end{gathered}$

The rocket splashes after 26.845 seconds.

The maximum of this function happens at the root of the derivative. Differentiating our function, we have