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Anni [7]
3 years ago
13

what is range of the inverse of the relation {(1, 7), (-2, 4), (5, 6), (2, 8)} A. {1, 2,5} B. {-4, 6, 7, 8} C. {1, 5} D. {-4, 7,

8}
Mathematics
1 answer:
Rufina [12.5K]3 years ago
8 0
The answer should be the domain of this relation. {-2, 1, 2, 5} but I do not see that as one of your answer choices.

The inverse of a relation is when you switch the domain and range.  In other words, the domain of the original relation becomes the range of the inverse.
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Sean's house is currently worth $188,900. According to a realtor, house prices in Sean's neighborhood will increase by 4.8% ever
mrs_skeptik [129]

Answer  

Given

Sean's house is currently worth $188,900.

According to a realtor, house prices in Sean's neighborhood will increase by 4.8% every year.

To prove

Formula

Compound\quaterly\ interest = Principle (1 + \frac{r}{4})^{4t}

Where r is the rate in the decimal form.

As given

Take\ Principle\ = P_{0}

Rate = \frac{4.8}{100}

              = 0.048

Put in the formula

Compound\quaterly\ interest = P_{0}(1 + \frac{0.048}{4})^{4t}

Compound\quaterly\ interest = P_{0} (1 + \frac{0.048}{4})^{4t}

Compound\quaterly\ interest = P_{0} (1 + 0.012)^{4t}       Compound\quaterly\ interest = P_{0} (1.012)^{4t}  

Now also calculated monthly.

Formula

Compound\ monthly = Principle (1 + \frac{r}{12})^{12t}

As given

Take\ Principle\ = P_{0}

Rate = \frac{4.8}{100}

              = 0.048

Put in the formula

Compound\ monthly = P_{0} (1 + \frac{0.048}{12})^{12t}

Compound\ monthly = P_{0} (1 + 0.004)^{12t}

Compound\ monthly = P_{0} (1.004)^{12t}

As the approximation quarterly growth rate of the value of sean's house is near the Compounded quarterly interest .

Thus Option (A) is correct.

i.e

The expression (1.0118)^{4t} reveals the approximate quarterly growth rate of the value of Sean's house.




                                               

                                                       




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