A triangle, ABC, has coordinates A (-2, 0), B (-2, 5) and C (-4, 0). What is the length of the shortest side?
1 answer:
Answer: 2 units.
Step-by-step explanation: When you graph the points given, it gives you this shape in the image below. The hypotenuse (longest side of triangle) is found by doing the following:
a^2 + b^2 = c^2, where a and b are the legs (the other sides of the triangle) and c is the hypotenuse.
5^2 + 2^2 = 29.
√ 29 ≈ 5.38, and that is the length of the hypotenuse.
The shortest side is the bottom side, which is 2 units. Therefore, that is your answer.
Let me know if this is right! :)
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Answer:
second option
Step-by-step explanation:
Given
+ 6x² + 5 = 0
let u = x², then
u² + 6u + 5 = 0 ← in standard form
(u + 1)(u + 5) = 0 ← in factored form
Equate each factor to zero and solve for u
u + 1 = 0 ⇒ u = - 1
u + 5 = 0 ⇒ u = - 5
Change u back into terms of x, that is
x² = - 1 ( take the square root of both sides )
x = ± = ± i ( noting that
= i ), and
x² = - 5 ( take the square root of both sides )
x = ± = ±
= ±
×
= ± i
Solutions are x = ± i and x = ± i