For the first one the nth term is 9n - 8 so the 10th term is 9x10 - 8 = 90-8 = 82
For the second one the nth term is ⅓n + ⅓ so the 11th term is ⅓x11 +⅓ = 3.9999 = 4
Answer:
(f o h)(x) = -10x + 32
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = 2x³ + 8
h(x) = ∛(12 - 5x)
(f o h)(x) is f(h(x))
<u>Step 2: Find Composite Function</u>
- Substitute: (f o h)(x) = 2(∛(12 - 5x))³ + 8
- Evaluate: (f o h)(x) = 2(12 - 5x) + 8
- Distribute 2: (f o h)(x) = 24 - 10x + 8
- Combine like terms: (f o h)(x) = -10x + 32
And we have our final answer!
Answer:
5.6 quarts
Step-by-step explanation:
x + .15(8) = .50(8+x)
x + 1.2 = 4
.50x + 1.2 = 4
.50x = 2.8
x = 2.8/.50
x = 5.6 quarts
Zoom in I think I know this