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4 years ago

2.8n-0.9p-3.4n+1.1p simplify

Mathematics

1 answer:

Natasha_Volkova [10]4 years ago

8 0

Answer:

2.8n-.9p-3.4n+1.1p

-0.6n+0.2p

You do 2.8n - 3.4n = -0.6 and -0.9p+1.1p = 0.2

(I made the answer bold)

Step-by-step explanation:

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By noon, the temperature increased 21 from the morning low -13 what was was the tempature noon

torisob [31]

-13+21=14
The temperature is 14 degrees during your afternoon.

5 0

3 years ago

[50 pts] An even number, n, times the next consecutive number, n + 2, is equal to 168. Find the original number.

ale4655 [162]

We are given:

An even number 'n', multiplied by the next consecutive even number is 168

Solving for n:

From the given statement, we can say that:

n(n+2) = 168 [n multiplied by the next even number 'n+2']

n² + 2n = 168

n² + 2n - 168 = 0 [subtracting 168 from both sides]

We can see that we now have a quadratic equation, solving using splitting the middle term

n² + 14n - 12n - 168 = 0

n(n + 14) -12(n + 14) = 0 [factoring out common terms]

(n-12)(n+14) = 0

Here, we can divide both sides by either (n-12) OR (n+14)

Checking the result in both the cases:

(n + 14) = 0/(n-12) (n-12) = 0/(n+14)

n + 14 = 0 n - 12 = 0

n = -14 n = 12

Both these values are even and since we are not told if the number 'n' is positive or negative, both 12 and -14 are the possible values of n

4 0

3 years ago

Logx = 1 - log(x-9) how do you solve this?

andrew-mc [135]

Get the app Symbolab, it helped me when I was learning about logarithms.
The answer is x=10

3 0

3 years ago

Can y’all help plsss

gtnhenbr [62]

Answer:

ok so a way to do this is that

124-180=56

75-180=105

105+56= 161

180-161= 19

180-19=161

so A.

7 0

3 years ago

Read 2 more answers

29. BASKETBALL When Jerald shoots a free throw, the ball is 6 feet from the floor and has

tatuchka [14]

Answer:

a) j(t) = -16t^2 +20t +6

b) 1 second

c) less time

Step-by-step explanation:

The general equation for vertical motion is ...

$h(t)=-\dfrac{1}{2}gt^2+v_0t+h_0\\\text{where $v_0$ is the initial upward velocity, and $h_0$ is the initial height}$

a) j(t) = -16t^2 +20t +6 . . . . . filling in the given initial values, with g=32 ft/s^2

b) We want to find the larger of the solutions to ...

j(t) = 10 = -16t^2 +20t +6

Subtracting 6 and dividing by -4, we have ...

-1 = 4t^2 -5t

4t^2 -5t +1 = 0 . . . . add 1, put in standard form

(4t -1)(t -1) = 0 . . . . . factor

t = 1/4 or 1

The ball is in the air 1 second before reaching the hoop.

c) In generic terms, the equation of motion for a given shooting height at the same upward velocity will be ...

10 = -16t^2 +20t + h0

-16t^2 +20t +(h0 -10) = 0

Using the quadratic formula, we find the larger solution to be ...

t = (-(20) -√(20² -4(-16)(h0 -10)))/(2(-16))

t = (5/8) + √(64h0 -240)/32 = (5 +√(4h0 -15))/8

This value increases as h0 increases, so the ball will be in the air less time when Raymond shoots.

7 0

4 years ago