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ikadub [295]
2 years ago
12

How many ways can 6 people wait in line if Tom or John need to be last in line?

Mathematics
1 answer:
Maru [420]2 years ago
8 0

Answer:

I think it will over 30 ways but im not sure

hope this helps

have a good day :)

Step-by-step explanation:

You might be interested in
The CBGC pays college and high school students $5.75 per hour to tutor the younger boys and girls. If one of those tutors works
Levart [38]

Answer:

1. $35.075

2. 43.5 hours

3. 70%

4. Danny is correct

5. Abe's score out of the 30 points of the last quiz to get an overall checkup quiz grade of 80% should be 28.5

Step-by-step explanation:

The pay per hour for student tutors = $5.75

1. A tutor who worked 3.4 hours on Monday and 2.7 hours on Thursday has worked, 3.4 + 2.7 = 6.1 hours for the week, therefore

The week earning for the tutor = 6.1 × 5.75 = $35.075

2. The Club's tutoring budget per week = $250

The number of tutoring hours that can be provided per week is given by the relation;

\frac{The \, Club's \ tutoring\  budget \ per \, week}{The \, pay \ per \, hour\,  for\,  student\,  tutors} = \frac{\$250}{\$5.75/hour} = 43.47826  \approx 43.5 \, hours

3. The score of 21 out of 30 as a percentage is given as follows;

\frac{21}{30} \times 100 = 70\%

4. Where the second score is 45 out of a total of 60 points, we have;

\frac{45}{60} \times 100 = 75\%

Therefore, the increase in Abe's score is 5%, therefore, Danny is correct

5. To raise his checkup quiz grade to 80% overall, then we should have;

\frac{70 + 75 + Q}{300} =\frac{80}{100}

Where:

Q = The percentage grade of the last quiz

(145 + Q)×100 = 80×300 = 24000

145 + Q = 240

Q = 240 - 145 = 95%

Therefore, he has to score, 95% of 30 on the last quiz, which is thus;

\frac{95}{100} \times 30 = 28.5

Abe's score out of the 30 points of the last quiz to get an overall checkup quiz grade of 80% = 28.5 points.

7 0
3 years ago
for each road condition, find the maximum speed the car can travel without needing more than 60m to stop. (rsm questions)
Gre4nikov [31]

Answer:

45 mph the the middle one

Step-by-step explanation:

i did the same one and got 45 and its right

4 0
2 years ago
An object is launched from a launching pad 208 ft. above the ground at a velocity of 192ft/sec. what is the maximum height reach
Alexeev081 [22]

Answer:

h(x) = -16x² + 192x + 208

784ft

6 sec

13 sec

Step-by-step explanation:

a)

h(x) = -16x² +vx + h_{o}

here v represent velocity

         h_{o} represent initial height of launch

       

h(x) = -16x² + 192x + 208

b)

h(x) = -16x² + 192x + 208

here a = -16

        b = 192

        c = 208

x = -b/2a

  = -192/2(-16)

  = 6

plug this value in the equation

h(x) = -16(6)² + 192(6) + 208

      = 784ft

e)

Plug h(x)=0 in the equation

0 = -16x² + 192x + 208

divide equation by -16

x² - 12x - 13 = 0

Factors

1x * -13x = -13

1x - 13x = -12

Factorised form

x² - 12x - 13 = 0

x² + x - 13x - 13 = 0

x(x+1) -13(x+1) = 0

(x+1)(x-13) = 0

x = -1

x = 13

Since time can not be negative so we will reject x = -1  

3 0
3 years ago
Find the area of the figure. (Sides meet at right angles.)
daser333 [38]

Answer:

48m squared

Step-by-step explanation:

- cut the problem in half horizontally

you get two squares one square is 4 by 4 and the other 8 by 4

4 times 4=16 8 times 4=32  32+16=48

6 0
2 years ago
What is the slope of (1,-3) and (-5,-4)
egoroff_w [7]

Answer:

slope is 1/6

Step-by-step explanation:

3 0
3 years ago
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