The computation shows that the placw on the hill where the cannonball land is 3.75m.
<h3>How to illustrate the information?</h3>
To find where on the hill the cannonball lands
So 0.15x = 2 + 0.12x - 0.002x²
Taking the LHS expression to the right and rearranging we have:
-0.002x² + 0.12x -.0.15x + 2 = 0.
So we have -0.002x²- 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x² + 0.03x -2 = 0.
This is a quadratic equation with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25.
The second solution y = 0.15 * 25 = 3.75
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Complete question:
The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?
Answer:
132
Step-by-step explanation:
Answer:
The volume of the box is 
Step-by-step explanation:
we know that
The volume of the box is equal to
where
L is the length of the box in inches
W is the width of the box in inches
H is the height of the box in inches
we have
substitute in the formula
12v = 18+6v
move +6v to the other side
sign changes from +6v to -6v
12v-6v= 18+6v-6v
12v-6v= 18
6v= 18
divide by 6 to get v by itself
6v/6=18/6
Answer:
v= 3
Answer:
Step-by-step explanation:
