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dsp73
3 years ago
5

Let the experiment be the toss of six coins in a row. Let X be number of of coins that turn up heads. Determine whether the foll

owing statement is true or false: The event that X<3 and the event that X>3 are independent. Question 3 options: True False
Mathematics
1 answer:
Leni [432]3 years ago
5 0

Answer:

True

Step-by-step explanation:

When a coin is tossed six coins in a row, there are a total of 2^6 outcomes.

The possible number of times for a heads are {0, 1, 2, 3, 4, 5, 6}.

Let our random variable, Number of coins that turn up heads be X

X={0, 1, 2, 3, 4, 5, 6}.

The event that X<3 and the event that X>3 cannot occur simultaneously in the same outcome.

In an outcome, its either one of the following happens:

  • Number of heads = Number of Tails =3
  • Number of heads < Number of Tails
  • Number of heads > Number of Tails
  • Number of heads cannot be greater than Number of Heads

Therefore, the events that X<3 and X>3 are independent.

You might be interested in
find the circumference of the circle. d=23 in. a)144.44 in b)1661.06 in c)36.11 in d)72.22 in e)415.27 in
snow_lady [41]

Circumference of a circle = \pi (diameter)

Diameter = 23 in.

Plug in the diameter = 23 in in the formula of circumference given above

Circumference of a circle = \pi (23)

Circumference of a circle = 23 \pi

\pi = 3.14

Circumference of a circle = 23 (3.14)

Circumference of a circle = 72.22 in

Option D is the answer

4 0
3 years ago
Read 2 more answers
D(x)=(x^2-12x+20)/(3x)
krok68 [10]

Answers:

Vertical asymptote: x = 0

Horizontal asymptote: None

Slant asymptote: (1/3)x - 4

<u>Explanation:</u>

d(x) = \frac{x^{2}-12x+20}{3x}

      = \frac{(x-2)(x - 10)}{3x}

Discontinuities: (terms that cancel out from numerator and denominator):

Nothing cancels so there are NO discontinuities.

Vertical asymptote (denominator cannot equal zero):

3x ≠ 0  

<u>÷3</u>   <u>÷3 </u>

x ≠ 0

So asymptote is to be drawn at x = 0

Horizontal asymptote (evaluate degree of numerator and denominator):

degree of numerator (2) > degree of denominator (1)

so there is NO horizontal asymptote but slant (oblique) must be calculated.

Slant (Oblique) Asymptote (divide numerator by denominator):

  •        <u>(1/3)x - 4    </u>
  •    3x)    x² - 12x + 20
  •             <u>x²        </u>
  •                  -12x
  •                  <u>-12x         </u>
  •                             20 (stop! because there is no "x")

So, slant asymptote is to be drawn at (1/3)x - 4



6 0
3 years ago
The probability of a red marble being pulled from a bag full of colored marbles is
Mkey [24]
The answer is 5/7. That is the answer :)
6 0
3 years ago
Consider the two functions described below. Function 1 describes the cost, y, to park in a parking lot for x hours. There is a f
Len [333]

Statement B explains correctly that the parking garage charges a higher rate per hour than the parking lot. Statements B and D are the same.

Step-by-step explanation:

Step 1:

For the parking lot, there is a flat fee of $7.00 and then a charge of $1.00 every hour.

So if a vehicle was parked for 1 hour charges are 7 + 1 (1) = $8,

If parked for two hours charges are 7 + 1 (2) = $9.

Step 2;

To understand the pricing of the parking garage, we must plot the points of the graph.

The points on the graph are (0, 4), (1, 6), (2, 8), (3, 10), (4, 12), (5, 14)...

So for the parking garage, there is a flat fee of $4 and then a charge of $2.00 every hour.

So if a vehicle was parked for 1 hour charges are 4 + 2 (1) = $6,

If parked for two hours charges are 4 + 2 (2) = $8.

Step 3:

Comparing both the parking lot and the parking garage, we get that the flat fee for the parking lot is higher while the parking charges for an hour are higher for the parking garage which is statement B.

Statement B and D are the same.

7 0
3 years ago
A local store, Faith Ltd has two options to choose either Big Van or Small Van or both types of van to supply bags of rice to lo
Nady [450]

Answer:

Cheapest cost to pay = £906

Step-by-step explanation:

Given that:

Rice to supply = 50 tonnes

Option A:

Big van has capacity of 15 tonnes.

Number of big vans = \frac{50}{15}=3.33

It means that 4 big vans will be needed for transporting 50 tonnes of rice.

Cost of 4 vans = 4*250 = £1000

Option B:

Small van has capacity of 9 tonnes.

Number of small vans = \frac{50}{9} = 5.55

It means that 6 small vans will be nedded for transporting 50 tonnes of rice.

Cost of 6 vans = 6*151 = £906

Therefore,

The company can transport the rice through small vans.

Hence,

Cheapest cost to pay = £906

6 0
3 years ago
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