When there is no prior information for the population proportion, then the formula we use to find the sample size to estimate the confidence interval :

$n=0.25(\dfrac{z^*}{E})^2$ , where z* = Critical z-value and E + amrgin of error.

Let p = proportion of packages of ground beef sold at a particular store that have an actual fat content exceeding the fat content stated on the label.

Since , we have no prior information about p. so we use above formula

with E = 0.06 and critical value for 95% confidence =z* =1.96 [By z-table ] , we get

$n=0.25(\dfrac{1.96}{0.06})^2=0.25(32.6666)^2\\\\=(0.25)(1067.111111)\\\\=266.777777778\approx267$

Hence, the required sample size is 267.

7 0

3 years ago

Pls answer ASAP timed assignment

ddd [48]

Answer:

A and C

Step-by-step explanation:

4 0

3 years ago

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Help with math pls its easy i think

grigory [225]

6. 1 is at the bottom and 6 is at the top.

8 0

2 years ago

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the longest side of an acute isosceles triangle 8 centimeters . Round to the nearest tenth, what is the smallest possible length

Triss [41]

Let x be the <span>length of each of two congruent sides.

</span>The triangle will be аcute if:
x² + x² > 8²
2x² > 64
x² > 32
x > √32
x > 5.657

So, the smallest possible length of one of two congruent sides have to be 5.7 cm (<span>to the nearest tenth)</span>

7 0

3 years ago

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