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Lady bird [3.3K]
3 years ago
15

Why is looking at cash flow an important step in a good financial plan?

Mathematics
2 answers:
leva [86]3 years ago
5 0
To keep knowing how much money you have i reccomend credit karma to help but money is very important
jeka943 years ago
3 0

Answer:

To keep knowing how much money you have i recommend credit karma to help but money is very important


Step-by-step explanation:


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PLZ PLZ PLZZZZZZ HELP ME IMMEDIATLEY
earnstyle [38]

Answer:

×=64

I HOPE IT CAN HELP:(

8 0
2 years ago
Write the equation of the line that passes through (−3,1) and (2,−1) in slope-intercept form
Alex787 [66]

Answer:

y=-\frac{2}{5}x-\frac{1}{5}

Step-by-step explanation:

The equation of a line is y = mx + b

Where:

  • m is the slope
  • b is the y-intercept

First, let's find what m is, the slope of the line.

Let's call the first point you gave, (-3,1), point #1, so the x and y numbers given will be called x1 and y1.

Also, let's call the second point you gave, (2,-1), point #2, so the x and y numbers here will be called x2 and y2.

Now, just plug the numbers into the formula for m above, like this:

m = -\frac{2}{5}

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=-\frac{2}{5}x + b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

  • (-3,1). When x of the line is -3, y of the line must be 1.
  • (2,-1). When x of the line is 2, y of the line must be -1.

Now, look at our line's equation so far: y=-\frac{2}{5}x + b. b is what we want, the --\frac{2}{5} is already set and x and y are just two 'free variables' sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-3,1) and (2,-1).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!

You can use either (x,y) point you want. The answer will be the same:

  • (-3,1). y = mx + b or 1=-\frac{2}{5} * -3 + b, or solving for b: b = 1-(-\frac{2}{5})(-3).b = -\frac{1}{5}.
  • (2,-1). y = mx + b or -1=-\frac{2}{5} * 2 + b, or solving for b: b = 1-(-\frac{2}{5})(2). b = -\frac{1}{5}.

See! In both cases, we got the same value for b. And this completes our problem.

The equation of the line that passes through the points  (-3,1) and (2,-1) is y=-\frac{2}{5}x-\frac{1}{5}

8 0
2 years ago
Wes had 4.75 in quarters and dimes if he had 25 coins how many of each did he have?
Verizon [17]

Answer:it would be 15 quarters and 10 dimes

Step-by-step explanation:

15 quarters is 3.75 and 10 dimes is $1, add them up you get $ 4.75

5 0
3 years ago
Read 2 more answers
The area of rhombus ABCD is 72 square units. EC = 8 units and DB = x – 1.
Tatiana [17]
The answer is 10
10-1=9
9*8=72
5 0
3 years ago
#1-7<br><br> 10 points!!!!<br><br> please help :)
Contact [7]
1. A
2. D
3. C
4. 5n
5. 24 ?
6. 80
7. 5

they may not be right i honestly dont know but hopefully it helps just a little :’)
4 0
3 years ago
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