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Rom4ik [11]
2 years ago
10

Which of the following shows the simplified function of csc x sin(pi/2 -x)?

Mathematics
1 answer:
alex41 [277]2 years ago
6 0

Answer:

cot x

Step-by-step explanation:

using the identities

csc x = \frac{1}{sinx}

sin(\frac{\pi }{2} - x) = cos x

then

csc x × sin (\frac{\pi }{2} - x)

= \frac{1}{sinx} × cosx

= \frac{cosx}{sinx}

= cot x

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Please help asap!:) Thank you!​
finlep [7]

Answer:

(f + g)(3) = 9

Step-by-step explanation:

Given:

f(x) = x² + 1

g(x) = x - 4

Required:

(f + g)(3)

SOLUTION:

✔️Find f(3) by substituting x = 3 into f(x) = x² + 1:

f(3) = (3)² + 1 = 9 + 1

f(3) = 10

✔️Find g(3) by substituting x = 3 into g(x) = x - 4:

g(3) = 3 - 4

g(3) = -1

✔️Find (f + g)(3):

(f + g)(3) = f(3) + g(3)

= 10 + (-1)

= 10 - 1

(f + g)(3) = 9

4 0
3 years ago
A kite is a quadrilateral with two pairs of adjacent, congruent sides. The vertex angles are those angles in between the pairs o
ExtremeBDS [4]
Try the answer vertex
7 0
3 years ago
An irregular polygon is shown below:
Liono4ka [1.6K]
You can split this shape into two shapes; a rectangle on top and a horizontal rectangle underneath. The top rectangle would be 4 x 2 = 8 square units, and the bottom rectangle would be 7 x 1 (3 - 2) = 7 square units. Now you just add these to get 15 square units. I hope this helps!
5 0
3 years ago
Read 2 more answers
7034 x 10^9 in standard notation
fgiga [73]

Answer:

= 7034000000000

(real number)

= 7.034 × 1012

(scientific notation)

= 7.034e12

(scientific e notation)

= 7.034 × 1012

(engineering notation)

(trillion; prefix tera- (T))

= 7034000000000

(real number)

Step-by-step explanation:

Convert Scientific Notation to a Real Number

Multiply the decimal number by 10 raised to the power indicated.

Examples:

3.456 x 10^4 = 3.456 x 10,000 = 34560

3.456 x 10^-4 = 3.456 x .0001 = 0.0003456

5 0
3 years ago
Find u and v only please:
tekilochka [14]

Every two triangles are similar. Therefore the sides of triangles are in proportion.

We have the equations:

1.

\dfrac{3}{5}=\dfrac{3+x}{20}    <em>cross multiply</em>

5(3+x)=(3)(20)      <em>divide both sides by 5</em>

3+x=(3)(4)

3+x=12      <em>subtract 3 from both sides</em>

\boxed{x=9}

--------------------------------------

2.

\dfrac{3}{4}=\dfrac{9}{y}      <em>cross multiply</em>

3y=(4)(9)

3y=36      <em>divide both sides by 3</em>

\boxed{y=12}

------------------------------------------

3.

\dfrac{3}{5}=\dfrac{3+9+u}{60}

\dfrac{3}{5}=\dfrac{12+u}{60}    <em>cross multiply</em>

5(12+u)=(3)(60)      <em>divide both sides by 5</em>

12+u=(3)(12)

12+u=36      <em>subtract 12 from both sides</em>

\boxed{u=24}

----------------------------------------------

4.

\dfrac{3}{4}=\dfrac{24}{v}              <em>cross multiply</em>

3v=(4)(24)

3v=96      <em>divide both sides by 3</em>

\boxed{v=32}

3 0
3 years ago
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