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Yuri [45]
3 years ago
9

3 × 5/8 + 3,200 ÷ 3?

Mathematics
1 answer:
MariettaO [177]3 years ago
6 0

\bf 3\times \cfrac{5}{8}+3200\div 3\implies \stackrel{\stackrel{ 3\times \frac{5}{8}}{\downarrow }}{\cfrac{15}{8}}+3200\div 3 \\\\\\ \cfrac{15}{8}+\stackrel{\stackrel{3200\div 3}{\downarrow }}{\cfrac{3200}{3}}\implies \stackrel{\textit{using an LCD of 24}}{\cfrac{(3)15+(8)3200}{24}}\implies \cfrac{45+25600}{24} \\\\\\ \cfrac{25645}{24}\implies 1068\frac{13}{24}


recall MD are first, from left to right, and lastly AS, also from left to right.

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2. Starting at a fixed time, each car entering an intersection is observed to see whether it turns left (L), right (R), or goes
jasenka [17]

Answer:

Natural numbers (integers greater than zero)

X = 3,  5,  4,  4,  3

Step-by-step explanation:

The least number of cars that can be observed in this experiment is 1, if the first car turns left. On the other hand, the experiment could go on forever if no car ever turns left, thus the highest number of cars approaches infinite.

The possible values of X are integers greater than zero, which are known as the Natural numbers.

If X = number of cars observed, simply count the number of letters in each outcome for the value of X:

Outcome = RRL, AARRL, AARL, RRAL, ARL

            X = 3,  5,  4,  4,  3

7 0
3 years ago
How do i write seven thousand, two hundred fifty-six and thirty-five hundredths in expanded form
Phoenix [80]
7,000 + 200 + 50 + 6 + 0.3 + 0.05

7,256.35
3 0
3 years ago
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Alika [10]
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5 0
3 years ago
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Sean places 28 tomato plants in rows. All rows contain the same number of plants. There are netween 5 and 12 plants in each row.
IrinaVladis [17]

Answer:

4 rows of 7 plants each

Step-by-step explanation:

To find the number of plants in each row between 5 and 12 requires us to find the factors of the total 28.

28 has factors 1,28 and 2,14 and 4,7. Only 4,7 has a number between 5 and 12. There are 4 rows of 7 plants.

7 0
3 years ago
A bakery works out a demand function for its chocolate chip cookies and finds it to be q = D (x) = 943 - 17 x​, where q is the q
Alex73 [517]

Answer:

See expla below

Step-by-step explanation:

Given the demand function:

q = D (x) = 943 - 17 x

a) Find the elasticity:

Find the derivative of the demand function.

D'(x)= -17

Thus, elasticity expression is:

\frac{x D'(x)}{D'(x)}

= \frac{x (-17)}{943 - 17x}

= \frac{17x}{943 - 17x}

Elasticity expression = E(x) = \frac{17x}{943 - 17x}

b) At what price is the elasticity of demand equal to 1?

This means E(x) = 1

Substitute 1 for E(x) in the elasticity equation:

E(x) = \frac{17x}{943 - 17x}

1 = \frac{17x}{943 - 17x}

Cross multiply:

943 - 17x = 17x

Collect like terms

17x + 17x = 943

34x = 943

x = \frac{943}{34}

x = 27.74

Elasticity at the price of demand = 1 is 27.74

c) At what prices is the elasticity of demand elastic?

This means E(x) > 1

Therefore,

\frac{17x}{943 - 17x} > 1

\frac{17x}{943 - 17x} > 1

Cross multiply:

17x > 943 - 17x

Collect like terms

17x + 17x > 943

34x > 943

x > \frac{943}{34}

x > 27.74

The elasticity of demand is elastic at x > 27.74

d) At what prices is the elasticity of demand inelastic?

This means E(x) < 1

Therefore,

\frac{17x}{943 - 17x} < 1

\frac{17x}{943 - 17x} < 1

Cross multiply:

17x < 943 - 17x

Collect like terms

17x + 17x < 943

34x < 943

x < \frac{943}{34}

x < 27.74

The elasticity of demand is inelastic at x < 27.74

e) At what price is the revenue a maximum:

Total  revenue will be:

R(x) = x D(x)

= x (943 - 17x)

= 943x - 17x²

R(x) = 934 - 17x(price that maximizes total revenue)

Take R(x) = 0

Thus,

0 = 943 - 17x

17x = 943x

x = \frac{943}{17}

x = 27.74

Total revenue is maximun at x= 27.74 per cookie

f) At x = 21 per cookie, find the price:

Thus,

R (21) = (943 * 21) - (17 * 21²)

= 19803 - 7497

= 12306

At x = 27.74, find the price:

R(27.74) = (943 * 27.74) - (17 - 27.74²)

= 26158.82 - 13081.63

= 13077.19

We can see the new price of cookie causes the total revenue to decrease.

Therefore, with a small increase in price the total revenue will decrease.

5 0
3 years ago
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