To simplify this, you would have to turn b^-2 into a positive exponent.
To do this, we have to flip b^-2, which would get rid of the negate from the exponent: -2
3a^4 b^-2 c^3 / b^-2
Then we get the answer:
3a^4 c^3
------------
b^-2
I have a picture to clarify!
I hope this helped, let me know if you don't understand! ^.^
Step-by-step explanation:
r-5r-6s+8s-15
-4r+2s-15
= 2s-4r-15
Answer:
No, Lance's thinking is wrong because you cannot compare decimal numbers with alphabetizing words. For example, if we compare 37.6 to 7.42 using the method of Lance, we would probably say 37.6 is less than 7.42 because 3 is less than 7. But it is wrong. The 3 in 37.6 is in the tens place. On the other hand, 7.42 contains no tense. Therefore, 37.6 is actually higher.
Step-by-step explanation:
No, Lance's thinking is wrong because you cannot compare decimal numbers with alphabetizing words. For example, if we compare 37.6 to 7.42 using the method of Lance, we would probably say 37.6 is less than 7.42 because 3 is less than 7. But it is wrong. The 3 in 37.6 is in the tens place. On the other hand, 7.42 contains no tense. Therefore, 37.6 is actually higher.
Answer:
The answer to your question is 13 miles
Step-by-step explanation:
In the question is not mentioned the distance that Jose one during the afternoon, it is only mentioned that he ran faster than in the morning so we can imply that the distance was the same in both occasions, just he ran faster in the afternoon because there was no rain.
So, what is the case in which he uses the least coins? can he use 1 coin? no, there isn't a 35 cent coin. can he use 2 coins? yes! he can use 25+10 cent coins!
now, the largest number of coins means the coins of the smallest value: so using only 5 cent coins. How many would this be?
we have to divide:
35/5=7
so we would use 7 coins.
And the difference is 5: 7-2 is 5.
