A rocket moves upward as the engine pushes downward against exhaust gases and the exhaust gases push upward against the engine.
Explanation:
<em><u>GIVEN </u></em><em><u>:</u></em>
Work done(W) = 40 J
Time(t) = 4 s
Power (P) = ?
<em><u>We </u></em><em><u>know </u></em><em><u>that:</u></em>
W = P×t
Therefore,
P= W/t
=40/4
= 10 W
<em><u>Hope </u></em><em><u>it </u></em><em><u>helps</u></em>
Answer:
Q = 1.35*10⁻¹¹ C.
Explanation:
By definition, the capacitance of a capacitor, is the charge on one of the plates, divided by the potential difference between them, as follows:
At the same time, we can show (applying Gauss' Law to the surface of one of the plates), that the capacitance of a parallel-plate capacitor (with a dielectric of air), can be written as follows:
C = ε₀*A / d
Replacing by the values of A, and d, and taking into account that
ε₀ = 8.85*10⁻¹² F/m,
we get the value of the capacitance as follows:
C = 8.97*10⁻¹² F
As the voltage of an AA battery is 1.5 V, and is all applied to the capacitor, we can conclude that the charge on one of the plates is as follows:
Q = C* V = 8.97*10⁻¹² F* 1.5 V = 1.35*10⁻¹¹ C
Answer:
196J or 200J
Explanation:
Potential Energy = mgh
m( mass) = 10gm
h ( height) = 2m
g = 9.8 or 10 m/s ^2 ( choose whichever one is taught to you, usually in my school its 9.8 if the value isn't given )
PE = 10 × 10 × 2 = 200 J
or
PE = 10 × 9.8 × 2 = 196 J
Hope it helps