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2 years ago

Kai buys 6 fiction books and 4 nonfiction books.

Mathematics

2 answers:

Andru [333]2 years ago

8 0

answer is 3 : 2

because 6 fiction books and 4 nonfiction books so ratio is 6:4 = 3:2

vitfil [10]2 years ago

4 0

It's 3:2 I think because 6:4 needs to be simplified. The greatest common factor of 6 and 4 is 2. 2 can go in to 6, 3 times and 4, 2 times, and together is 3:2

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Katarina [22]

Answer:

hablas verja ijueputa mamaverja

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2 years ago

Carlos has $500 in his savings account that pays 3% simple interest. What is the amount of money Carlos will have in his bank ac

sleet_krkn [62]

Answer:

$1766

Step-by-step explanation:

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4 0

2 years ago

Read 2 more answers

Quick plz help asap marking brainliest for first answer as long as you include steps !!!

Akimi4 [234]

Answer:

a=2.48

c=9.52

Step-by-step explanation:

a+c=12

4a+7.5c=72.5 Given

a+c=12

-4a-7.5c=-72.5 multiply the equation by negative 1

-3a-6.5c=-60.5 simplify

-3a=-60.5+6.5c add 6.5c to both sides

a=-20.17+2.17c divide it by 3

now you would take that equation and plug it into an equation you already have since you have something to plug in for a, the easiest one to do is a+c=12

(-20.17+2.17c)+c=12 plug in the equation

-20.17+3.17c=12 simplify by solving for c

3.17c=30.17 add 20.17 to both sides

c=9.52 divide both sides by 3.17

now since you have found c, you can plug it in to you equation to solve for a now (use the ones from the second step). I am using the equation a+c=12.

a+9.52=12 plug in the variable and solve for a

a=2.48 subtract 9.52 to both sides

a=2.48

c=9.52

7 0

3 years ago

Mrs.gauthier plans to take her class on 2 field trips this year there are 23 students in her class and each field trip will cost

Alina [70]

If there is 2 field trips with 23 students and each student costs $5 dollars. So for the 1st trip it will be 23x$5

1st trip- $115

And on the second trip its the same because there is 23 students that cost 5 dollars so it will be 23x5

2nd trip- $115

To find out the total of both trips youd add 115+115/

In total, for both trips it will cost $230 dollars.

7 0

3 years ago

Country Financial, a financial services company, uses surveys of adults age and older to determine if personal financial fitness

Yakvenalex [24]

Complete Question

Country financials, a financial services company, uses surveys of adults age 18 and older to determine if personal financial fitness is changing over time. In February 2012, a sample of 1000 adults showed 410 indicating that their financial security was more that fair. In Feb 2010, a sample of 900 adults showed 315 indicating that their financial security was more than fair.

State the hypotheses that can be used to test for a significant difference between the population proportions for the two years.

What is the sample proportion indicating that their financial security was more that fair in 2012?In 2010?

Conduct the hypothesis test and compute the p-value.At a .05 level of significance what is your conclusion?

Answer:

The null hypothesis is $H_o : p_1 = p_2$

The alternative hypothesis is $H_a : p_1 \ne p_2$

in 2012 $\r p_1 =0.41$

in 2010 $\r p_2 =0.35$

The p-value is $p-value = 0.0072$

The conclusion is

There is sufficient evidence to conclude that the proportion of those indicating that financial security is more fair in Feb 2010 is different from the proportion of those indicating that financial security is more fair in Feb 2012.

Step-by-step explanation:

From the question we are told that

The sample size in 2012 is $n_1 = 1000$

The number that indicated that their finance was more than fail is k = 410

The sample size in 2010 is $n_2 = 900$

The number that indicated that their finance was more than fail is u = 315

The level of significance is $\alpha = 0.05[/ex]The null hypothesis is [tex]H_o : p_1 = p_2$

The alternative hypothesis is $H_a : p_1 \ne p_2$

Generally the sample proportion for 2012 is mathematically represented as

$\r p_1 = \frac{k}{n_1}$

=> $\r p_1 = \frac{410}{1000}$

=> $\r p_1 =0.41$

Generally the sample proportion for 2010 is mathematically represented as

$\r p_2 = \frac{u}{n_2}$

=> $\r p_2 = \frac{315}{900}$

=> $\r p_2 =0.35$

Generally the pooled sample proportion is mathematically represented as

$\r p = \frac{k + u }{n_1 + n_2}$

=> $\r p = \frac{410 + 315 }{1000+ 900}$

=> $\r p = 0.3816$

Generally the test statistics is mathematically represented as

$z = \frac{( \r p_1 - \r p_2 ) - 0}{\sqrt{\r p (1 - \r p ) ( \frac{1}{n_1} +\frac{1}{n_2} )} }$

$z = \frac{( 0.41 -0.35 ) - 0}{\sqrt{0.3816 (1 - 0.3816 ) ( \frac{1}{1000} +\frac{1}{900} )} }$

$z = 2.688$

Generally the p- value is mathematically represented as

$p-value = 2 P(Z >2.688 )$

From the z -table

$P(Z > 2.688) = 0.0036$

$p-value = 2 *0.0036$

$p-value = 0.0072$

So from the p-value obtained we see that p-value < $\alpha$ so we reject the null hypothesis

Thus there is sufficient evidence to conclude that the proportion of financial security is more fair in Feb 2010 is different from the proportion of financial security is more fair in Feb 2012.

5 0

3 years ago