Y-y1= m(x-x1) point-slope form
y-0= -3(x-5)
solve this point-slope form to slope-intercept form. Use the information to graph the line.
Find slope first:
m =y2-y1/x2-x1
m = 1--2/2--2
m = 3/4
Select a point, insert your slope, & put it into point slope form:
y-y1 =m(x-x1)
Your final answers are:
y-1=3/4(x-2)
OR
y+2 =3/4(x+2)
jake has 5 cats
then he finds 10 cats
jake now has 5+10 = 15 cats
now he loses 11 cats
15 -11 =4
jake now has 4 cats
Answer:
8:6
Step-by-step explanation:
If 8 out of 14 students are boys then the remaining number of students must be girls
So
14-8= 6
There are 6 girls out of the 14
So as a ratio of boys to girls
8:6
Answer: (751.05, 766.95)
Step-by-step explanation:
We know that the confidence interval for population mean is given by :-
,
where 
=population standard deviation.
= sample mean
n= sample size
z* = Two-tailed critical z-value.
Given : 
n= 42
We know that from z-table , the two-tailed critical value for 99% confidence interval : z* =2.576
Now, the 99% confidence interval around the true population mean viscosity :-
![759\pm (2.5760)\dfrac{20}{\sqrt{42}}\\\\=759\pm (2.5760)(3.086067)\\\\=759\pm7.9497=(759-7.9497,\ 759+7.9497)\]\\=(751.0503,\ 766.9497)\approx(751.05,\ 766.95)](https://tex.z-dn.net/?f=759%5Cpm%20%282.5760%29%5Cdfrac%7B20%7D%7B%5Csqrt%7B42%7D%7D%5C%5C%5C%5C%3D759%5Cpm%20%282.5760%29%283.086067%29%5C%5C%5C%5C%3D759%5Cpm7.9497%3D%28759-7.9497%2C%5C%20759%2B7.9497%29%5C%5D%5C%5C%3D%28751.0503%2C%5C%20766.9497%29%5Capprox%28751.05%2C%5C%20766.95%29)
∴ A 99% confidence interval around the true population mean viscosity : (751.05, 766.95)
