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3 years ago

6

Literally these are the only math problems I need help with I have so much homework bc I was out of school for a min and I just

need to catch up fast

1 answer:

Lesechka [4]3 years ago

7 0

Number 9 is number nine is x=-25

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debt payments of $800 due now and $1400 due in 5 months are to be repaid by a payment of $1000 in 3 months and a final payment i

loris [4]

Answer:

$1,304.70

Step-by-step explanation:

If interest 6% annually, monthly is 0.5%.

The debt in 5 months will be 800 plus compounded interest for 5 months plus new due debt

$800(1.005)^5+1400=2220.201$

In 3 more months the debt will be 2220.201 plus compounded interest for 3 months minus payment

$2220.201(1.005)^3-1000=1253.67$

After 8 months the debt would be 1253.67 plus compounded interest for 8 months

$2220.201(1.005)^3=1304.70$

Then the size of the final payment would be $1,304.70

5 0

3 years ago

Will give brainliest! please answer!

Montano1993 [528]

Answer:

Step-by-step explanation:

933 + the cost <=1500

933+ c <=1500

3 0

3 years ago

Read 2 more answers

Find the unknown side length, x. Write your answer in simplest radical form.

velikii [3]

The answer should be 16√5

8 0

3 years ago

Help!!!!!! I’ve been working on this for 1 hour

kifflom [539]

Answer:

7.83

Step-by-step explanation:

cos(40)=6/(ZX)

zx=7.83

5 0

3 years ago

What are the points for f(x)=3^(x-1)-2

Savatey [412]

Answer: (0, -1 $\frac{2}{3}$ ), (1, -1), (2, 1)

<u>Step-by-step explanation:</u>

Set the exponent equal to zero - <em>that is your anchor point</em>.

Then choose an x-value less than and greater than the anchor point.

$\left\begin{array}{c|c|l}&\underline{\quad x\quad }&\underline{\qquad \qquad f(x)\qquad \qquad \qquad \quad }\\\text{less than anchor}&0&3^{0-1}-2=3^{-1}-2=\frac{1}{3}-2 = -1\frac{2}{3}}\\\\anchor\ point&1&3^{1-1}-2=3^{0}-2=1-2 = -1}\\\\\text{greater than anchor}&2&3^{2-1}-2=3^{1}-2=3-2 = 1}\end{array}\right$

4 0

3 years ago