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Aleks [24]
3 years ago
13

square A has a side length (2x-7) and square B has side length (-4x+18) how much bigger is the perimeter of square B than square

A?
Mathematics
1 answer:
Paladinen [302]3 years ago
4 0
To make things easier, we can assume a value of x in order to substitute to each expression and obtain the side length of each. We can calculate for perimeter of each square. Then, compare them. We do as follows:

Assume x = 4
Square A
2x - 7 = 2(4) - 7 = 1
P = 4(1) = 4

Square B
-4x + 18 = -4(4) + 18 = 2
P = 4(2) = 8

Therefore, the perimeter of B is 2 than the perimeter of A.

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Two factors whose product is 84 are 12 and _[blank]_.
djyliett [7]

Answer: 7

Step-by-step explanation:

To solve this problem you must apply the proccedure shown below:

1. You know that a multiplication has the following form:

a*b=c

Where a and b are the factors and c is the product.

2. You know one of the factor, then you can find the second one as following:

12*b=84

b=84/12

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Therefore the answer is 7.

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Bumek [7]

Answer:

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Step-by-step explanation:

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den301095 [7]

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6 0
3 years ago
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Stels [109]
Your answer is 22:15
5 0
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Ray Of Light [21]

Answer:

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