Y=mx+b
m=slope
b=yintercept
given
y=-2x+3 and
y=-4x-1
first equation is slope -2 and yintercept 3
second is slope -4 and yintercept -1
3rd option
In this case we use intersecting secant theorem
According to this theorem, GF*GE = GH*GA
So,we plug in the values
(x-3)*(x-3+9) =(x-2)*(x-2+6)
(x-3)*(x+6) =(x-2)*(x+4)
x^2 +6x -3x -18 =x^2 +4x -2x -8
x^2 +3x -18 =x^2 +2x -8
x^2 +3x -18 -x^2 -2x +8 =0
x -10 =0
x=10
So,FG =x-3 = 10-3 =7
Answer: The polynomial 3x2 is of one variable with a degree of 2.
The polynomial x2y + 3xy2 + 1 is of two variables a with a degree of 3.
Step-by-step explanation: For this case we have the following polynomials:
3x2
x2y + 3xy2 + 1
We have then:
For 3x2:
Classification: polynomial of one variable:
Degree: 2
For x2y + 3xy2 + 1:
Classification: polynomial of two variables
Degree: 2 + 1 = 3
Answer:
If 40 wrong then I am sorry.
Step-by-step explanation:
Ok, so we know one point is (4,2) and the other is (-4, 0)
Slope: -2/-8 = 1/4
y ? 1/4x + b
0 = -1 + b
b = 1
y < 1/4x + 1
