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3 years ago

Please Help !!!

Mathematics

1 answer:

Rina8888 [55]3 years ago

7 0

Answer:

Step-by-step explanation:

Sums:

1, 3

2, 2

4, 0

31 and 22 are to small of numbers. That leaves 40.

40 and 04

so 40

- 04

____

= 36

Good luck,

Camryn :)

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If f(x)= x2/x+3, find f(x+h)?

kompoz [17]

f(x+h) = $\frac{x^{2}+2xh+h^{2} }{x+h+3}$

Step-by-step explanation:

Given,

f(x) = $\frac{x^{2} }{x+3}$

To find the value of f(x+h) we need to replace x by x+h

Hence,

f(x+h) = $\frac{(x+h)^{2} }{x+h+3}$

= $\frac{x^{2}+2xh+h^{2} }{x+h+3}$

[Here, we apply the formula of $(a+b)^{2}= a^{2} +2ab+ b^{2}$ ]

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2 years ago

Solve each trigonometric equation such that 0 ≤ x ≤ 2????. Give answers in exact form.

sveticcg [70]

Answer:

(a) $x=\frac{5\pi }{3}$

(b) $x=\frac{\pi }{8}$

Step-by-step explanation:

It is given that $0\leq x\leq 2\pi$

(a) We have given equation $2sinx+\sqrt{3}=0$

$sinx=\frac{-\sqrt{3}}{2}$

$x=sin^{-1}(-0.866)$

$x=\frac{-\pi }{3}=2\pi -\frac{\pi }{3}=\frac{5\pi }{3}$

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3 years ago

Felicia wants to build a kite with the shape shown. If AC is 60 cm, how many centimeters are in the length of BD?

Kay [80]

Answer:

Step-by-step explanation:

By applying tangent rule in the given right triangle AOB,

tan(30°) = $\frac{\text{Opposite side}}{\text{Adjacent side}}$

$\frac{1}{\sqrt{3}}=\frac{BO}{OA}$

$OA=BO(\sqrt{3})$

By applying tangent rule in the given right triangle BOC,

tan(60°) = $\frac{OC}{BO}$

OC = BO(√3)

OA + OC = AC

$BO(\sqrt{3})+BO(\sqrt{3}) =60$

2√3(BO) = 60

BO = 10√3

OC = BO(√3)

OC = (10√3)(√3)

OC = 30

By applying tangent rule in right triangle DOC,

tan(60°) = $\frac{OD}{OC}$

OD = OC(√3)

OD = 30√3

Since, BD = BO + OD

BD = 10√3 + 30√3

BD = 40√3

≈ 69.3

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2 years ago

Tim looks up at the top of a tree at an angle of elevation of 40 degrees. If heis 5 ft tall and 10 ft from the tree, how tall is

dolphi86 [110]

<h2>Answer:</h2>

13.391 ft

<h2>Explanations:</h2>

The schematic diagram of the given question is shown below;

The height of the tree is expressed as:

H = h +5

Determine the value of h using the SOH CAH TOA identity

$\begin{gathered} tan\theta=\frac{opposite}{adjacent} \\ tan40^0=\frac{h}{10} \\ h=10tan40 \\ h=10(0.8391) \\ h=8.391ft \\ \end{gathered}$

Determine the height of the tree

$\begin{gathered} H=h+5 \\ H=8.391+5 \\ H=13.391ft \end{gathered}$

Hence the height of the tree is 13.391ft

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6 months ago