Equation is <span>-4x+6y-5z=60
x-intercept is obtained by assuming y=0, z=0, and solving for x.
-4x+0-0=60 => x=-15, hence x-intercept is (-15,0,0)
Similarly for y-intercept, assume x=0,z=0 =>
0+6y-0=60 => y=60/6=10 => y-intercept is (0,10,0)
Again, for the z-intercept, assume x=0,y=0 =>
0+0-5z=60 => z=-12 => z-intercept is (0,0,-12)</span>
This would be no solution , there is none
Part A:
Given that <span>the mattress is sold for 50% off of the retail price, let the retail price of the mattress be x, then
50% of x = 1200
⇒ 0.5x = 1200
⇒ x = 1200 / 0.5 = 2400
Therefore, </span><span>the retail price of the mattress, before the discount is $2,400.
Part B:
Given that </span><span>the store marks up the retail price to 150% of the wholesale price. Let the whole sale price be p, then
(100% + 150%) of p = 2400
250% of p = 2400
2.5p = 2400
p = 2400 / 2.5 = 960.
Therefore, </span><span>the wholesale price, before the markup was $960</span>
You are given the information that he takes six lessons per week. First we will calculate the total lessons he could potentially take per year.
6 • 52 = 312
He could potentially take 312 lessons in one year.
Now that you know this information, you simply subtract the days he missed from that total.
312 - 5 = 307
Your final answer: Peter took 307 lessons during the year.
