Answer: B) It represents the product of two irrational numbers and is equivalent to an irrational number.
Step-by-step explanation:
1. By a definition an irrational number cannot be written as a simple fraction.
2. Keeping this information on mind:
(Cannot be written as a simple fraction. It is an irrational number).
(Cannot be written as a simple fraction. It is an irrational number).
3. When you multiply this irrational number, you obtain:
4. 
is an irrational number.
5. Therefore, the answer is the option B,
Answer:
How many boys are there in total? We can't answer correctly until you give us all the information.
Step-by-step explanation:
Answer:
A polynomial function that meet the conditions is x³ - 8x² + 5x + 14 = 0
Step-by-step explanation:
Hi there!
Let´s start writting a generic factored function. In this case, the function has 3 zeros so that the factored form will have 3 terms:
(x + a)(x + b)(x + c) = 0
For this expression to be 0, either (x+a) = 0 or (x+b) = 0 or (x+c) = 0
Then:
x + a = 0 ⇒ x = -a
x + b = 0 ⇒ x = -b
x + c = 0 ⇒ x = -c
Then, the values "a", "b" and "c" are equal to the zeros of the function but with opposite sign. Then, in our case:
a = 1
b = -2
c = -7
Then, the polynomial fuction will be:
(x + 1)(x - 2)(x - 7) = 0
Apply distributive property:
(x² - 2x + x -2)(x -7) = 0
(x² - x - 2)(x - 7)
x³ - x² - 2x - 7x² + 7x + 14 = 0
x³ - 8x² + 5x + 14 = 0
Then, a polynomial function that meets the conditions is:
x³ - 8x² + 5x + 14 = 0
Have a nice day!
Answer:
Step-by-step explanation:
With a factor of (t - 1) we know that zero (ground level) is reached at 1 second from an initial height of (0 - 1)(0 - 1)(0 - 11)(0 - 13)/3 = -1•-1•-11•-13 / 3 = 47⅔ meters at t = 0
As we have <em>two </em>factors of (t - 1) we know the track does not go underground at t = 1, but rises again.
At t = 11 seconds, the car has again returned to ground level, but as we only have a single factor of (t - 11) the car plunges below ground level and returns to above ground level at t = 13 seconds due to the single factor of (t - 13)
we can estimate that the car is the deepest below ground level halfway between 11 and 13 s, so at t = 12. At that time, the depth will be about (12 - 1)(12 - 1)(12 - 11)(12 - 13) / 3 = -(11²/3) = - 40⅓ m.
we can estimate that the car is the highest above ground level halfway between 1 and 11 s, so at t = 6s. At that time, the height will be about (6 - 1)(6 - 1)(6 - 11)(6 - 13) / 3 = 5²•-5•-7 / 3 = 291⅔ m.
It's obvious that the roller coaster car had significant initial velocity at t = 0 to achieve that altitude from an initial height of 47⅔ m
